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In the given figure AOB is a diameter of the circle with center O and AC is a tangent to the circle at A If angle BOC =130?
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In the given figure AOB is a diameter of the circle with center O and ...
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In the given figure AOB is a diameter of the circle with center O and ...
Given information:
- In the given figure, AOB is a diameter of a circle with center O.
- AC is a tangent to the circle at A.
- Angle BOC is given as 130°.

Proof:
To prove that angle BOC is 130°, we will use the properties of angles in a circle.

1. Angle in a semicircle:
- A diameter of a circle divides the circle into two equal parts, known as semicircles.
- The angle formed at any point on the circumference of a circle, when the lines joining the point to the endpoints of a diameter, is always 90°.
- Therefore, angle BOC is a right angle, and its measure is 90°.

2. Tangent and radius:
- A tangent to a circle is perpendicular to the radius drawn from the center of the circle to the point of contact.
- In the given figure, AC is a tangent to the circle at A.
- Therefore, angle OAC is 90°.

3. Angle sum property:
- In a triangle, the sum of all angles is always 180°.
- In triangle OAC, angle OAC + angle OCA + angle OAC = 180°.
- Since angle OAC and angle OCA are both 90° (as proved in the previous steps), we can substitute their values into the equation.
- 90° + 90° + angle OAC = 180°.
- Simplifying the equation, we get angle OAC = 0°.

4. Exterior angle property:
- The measure of an exterior angle of a triangle is equal to the sum of the measures of its interior opposite angles.
- In triangle OAC, angle OAC is the exterior angle.
- The interior opposite angles are angle OCA and angle OAC (both 90°).
- Therefore, angle OAC = angle OCA + angle OAC.
- Simplifying the equation, we get angle OCA = 0°.

5. Angle BOC:
- Angle BOC is formed by the lines OB and OC, which are radii of the circle.
- The measure of angle BOC is equal to the sum of the measures of angles OCA and OCB.
- From the previous steps, we know that angle OCA = 0°.
- Therefore, angle BOC = angle OCB + angle OCA = angle OCB + 0°.
- Simplifying the equation, we get angle BOC = angle OCB.

Conclusion:
- Angle BOC is a right angle (90°) and angle OCB is equal to angle BOC.
- Therefore, angle BOC = angle OCB = 90°.
- The given angle BOC is 130°, which contradicts our conclusion.
- Hence, there is an error in the given information or figure.
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In the given figure AOB is a diameter of the circle with center O and AC is a tangent to the circle at A If angle BOC =130?
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In the given figure AOB is a diameter of the circle with center O and AC is a tangent to the circle at A If angle BOC =130? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about In the given figure AOB is a diameter of the circle with center O and AC is a tangent to the circle at A If angle BOC =130? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the given figure AOB is a diameter of the circle with center O and AC is a tangent to the circle at A If angle BOC =130?.
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