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The Boolean expression XY + (X' + Y') Z is equivalent to
  • a)
    XYZ' + X'Y'Z
  • b)
    X'Y'Z' + XYZ
  • c)
    (X + Z) (Y + Z)
  • d)
    (X' + Z) (Y'Z)
Correct answer is option 'C'. Can you explain this answer?
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The Boolean expression XY + (X + Y) Z is equivalent toa)XYZ + XYZb)XYZ...
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The Boolean expression XY + (X + Y) Z is equivalent toa)XYZ + XYZb)XYZ...
Explanation:

The given Boolean expression is XY (X Y) Z.

We can simplify this expression using the distributive law of Boolean algebra, which states that:

X (Y Z) = XY XZ

Using this law, we can rewrite the expression as:

XY (X Y) Z
= XY XZ YZ (Applying distributive law)
= X (Y Z) YZ (Grouping like terms)
= (X Z) (Y Z) (Applying distributive law)

Therefore, the given Boolean expression XY (X Y) Z is equivalent to (X Z) (Y Z).

Hence, the correct answer is option C, (X Z) (Y Z).

Note: The distributive law is a very useful tool in simplifying Boolean expressions. It helps to reduce the number of terms and makes the expression easier to work with.
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The Boolean expression XY + (X + Y) Z is equivalent toa)XYZ + XYZb)XYZ + XYZc)(X + Z) (Y + Z)d)(X + Z) (YZ)Correct answer is option 'C'. Can you explain this answer?
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