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An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ball is placed back into the urn along with another ball of the same colour. The probability of getting a red ball in the next draw is
- a)65 / 156
- b)67 / 156
- c)79 / 156
- d)89 / 156
Correct answer is option 'A'. Can you explain this answer?
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An urn contains 5 red and 7 green balls. A ball is drawn at random and...
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An urn contains 5 red and 7 green balls. A ball is drawn at random and...
The Problem
An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ball is placed back into the urn along with another ball of the same colour. We need to find the probability of getting a red ball in the next draw.
Analysis
To solve this problem, we need to consider two scenarios:
1. The first ball drawn is red.
2. The first ball drawn is green.
Scenario 1: The first ball drawn is red
In this case, the probability of drawing a red ball is 5/12 (since there are 5 red balls and a total of 12 balls in the urn). After drawing the first red ball, it is placed back in the urn along with another red ball. So the total number of balls in the urn remains the same (12).
Scenario 2: The first ball drawn is green
In this case, the probability of drawing a green ball is 7/12 (since there are 7 green balls and a total of 12 balls in the urn). After drawing the first green ball, it is placed back in the urn along with another green ball. So the total number of balls in the urn remains the same (12).
Calculating the probability
To calculate the probability of getting a red ball in the next draw, we need to consider both scenarios and add up the probabilities.
Probability of the first ball being red * Probability of getting a red ball in the next draw given the first ball was red:
(5/12) * (6/12) = 30/144
Probability of the first ball being green * Probability of getting a red ball in the next draw given the first ball was green:
(7/12) * (5/12) = 35/144
Adding up the probabilities:
(30/144) + (35/144) = 65/144
Simplifying the fraction:
65/144 = 13/28
Therefore, the probability of getting a red ball in the next draw is 13/28.
Conclusion
The correct answer is option 'A' (65/156).
An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ball is placed back into the urn along with another ball of the same colour. We need to find the probability of getting a red ball in the next draw.
Analysis
To solve this problem, we need to consider two scenarios:
1. The first ball drawn is red.
2. The first ball drawn is green.
Scenario 1: The first ball drawn is red
In this case, the probability of drawing a red ball is 5/12 (since there are 5 red balls and a total of 12 balls in the urn). After drawing the first red ball, it is placed back in the urn along with another red ball. So the total number of balls in the urn remains the same (12).
Scenario 2: The first ball drawn is green
In this case, the probability of drawing a green ball is 7/12 (since there are 7 green balls and a total of 12 balls in the urn). After drawing the first green ball, it is placed back in the urn along with another green ball. So the total number of balls in the urn remains the same (12).
Calculating the probability
To calculate the probability of getting a red ball in the next draw, we need to consider both scenarios and add up the probabilities.
Probability of the first ball being red * Probability of getting a red ball in the next draw given the first ball was red:
(5/12) * (6/12) = 30/144
Probability of the first ball being green * Probability of getting a red ball in the next draw given the first ball was green:
(7/12) * (5/12) = 35/144
Adding up the probabilities:
(30/144) + (35/144) = 65/144
Simplifying the fraction:
65/144 = 13/28
Therefore, the probability of getting a red ball in the next draw is 13/28.
Conclusion
The correct answer is option 'A' (65/156).
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An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer?
Question Description
An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer?.
An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer?.
Solutions for An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer?, a detailed solution for An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An urn contains 5 red and 7 green balls. A ball is drawn at random and its colour is noted. The ballis placed back into the urn along with another ball of the same colour. The probability of getting ared ball in the next draw isa)65 / 156b)67 / 156c)79 / 156d)89 / 156Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice GATE tests.
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