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Nazima is fly fishing in a stream the tip of her fishing rod is 1.8 metre above the surface of the water And the fly at the end of the string rests On The Water 3.6 metre away and 2.4 away from a point directly under the tip of the rod as assuming that her string from the tip of her rod to the fly is taut how much string does she have out? if she pulls in the string at the rate 5cm per second what will be the horizontal distance of the fly from her after 12 seconds?can anyone please answer?
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Given Information:
- The tip of Nazima's fishing rod is 1.8 meters above the surface of the water.
- The fly at the end of the string rests 3.6 meters away from the tip of the rod.
- The fly is also 2.4 meters away from a point directly under the tip of the rod.
- The string from the tip of the rod to the fly is taut.
Finding the Length of the String:
To find the length of the string, we can use the Pythagorean theorem.
- The horizontal distance from the tip of the rod to the fly is 3.6 meters.
- The vertical distance from the tip of the rod to the point directly under the fly is 1.8 meters.
Using the Pythagorean theorem, we can calculate the length of the string:
string length = √(3.6^2 + 1.8^2)
Calculating the Length of the String:
- Calculate the square of the horizontal distance: 3.6^2 = 12.96
- Calculate the square of the vertical distance: 1.8^2 = 3.24
- Add the squares of the distances together: 12.96 + 3.24 = 16.2
- Take the square root of the sum: √16.2 = 4.02
Therefore, the length of the string is approximately 4.02 meters.
Calculating the Horizontal Distance of the Fly:
- Nazima pulls in the string at a rate of 5 cm per second.
- She wants to know the horizontal distance of the fly after 12 seconds.
To calculate the horizontal distance of the fly, we need to find the total distance pulled in by Nazima in 12 seconds.
- Convert the rate of pulling in the string to meters per second: 5 cm = 0.05 meters
- Multiply the rate by the time: 0.05 meters/second * 12 seconds = 0.6 meters
Therefore, Nazima would have pulled in a total of 0.6 meters of string.
To find the new horizontal distance of the fly, we subtract the total distance pulled in from the initial horizontal distance.
- Initial horizontal distance: 3.6 meters
- Total distance pulled in: 0.6 meters
- New horizontal distance: 3.6 meters - 0.6 meters = 3 meters
After 12 seconds, the fly would be approximately 3 meters away from Nazima horizontally.
- The tip of Nazima's fishing rod is 1.8 meters above the surface of the water.
- The fly at the end of the string rests 3.6 meters away from the tip of the rod.
- The fly is also 2.4 meters away from a point directly under the tip of the rod.
- The string from the tip of the rod to the fly is taut.
Finding the Length of the String:
To find the length of the string, we can use the Pythagorean theorem.
- The horizontal distance from the tip of the rod to the fly is 3.6 meters.
- The vertical distance from the tip of the rod to the point directly under the fly is 1.8 meters.
Using the Pythagorean theorem, we can calculate the length of the string:
string length = √(3.6^2 + 1.8^2)
Calculating the Length of the String:
- Calculate the square of the horizontal distance: 3.6^2 = 12.96
- Calculate the square of the vertical distance: 1.8^2 = 3.24
- Add the squares of the distances together: 12.96 + 3.24 = 16.2
- Take the square root of the sum: √16.2 = 4.02
Therefore, the length of the string is approximately 4.02 meters.
Calculating the Horizontal Distance of the Fly:
- Nazima pulls in the string at a rate of 5 cm per second.
- She wants to know the horizontal distance of the fly after 12 seconds.
To calculate the horizontal distance of the fly, we need to find the total distance pulled in by Nazima in 12 seconds.
- Convert the rate of pulling in the string to meters per second: 5 cm = 0.05 meters
- Multiply the rate by the time: 0.05 meters/second * 12 seconds = 0.6 meters
Therefore, Nazima would have pulled in a total of 0.6 meters of string.
To find the new horizontal distance of the fly, we subtract the total distance pulled in from the initial horizontal distance.
- Initial horizontal distance: 3.6 meters
- Total distance pulled in: 0.6 meters
- New horizontal distance: 3.6 meters - 0.6 meters = 3 meters
After 12 seconds, the fly would be approximately 3 meters away from Nazima horizontally.
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Nazima is fly fishing in a stream the tip of her fishing rod is 1.8 metre above the surface of the water And the fly at the end of the string rests On The Water 3.6 metre away and 2.4 away from a point directly under the tip of the rod as assuming that her string from the tip of her rod to the fly is taut how much string does she have out? if she pulls in the string at the rate 5cm per second what will be the horizontal distance of the fly from her after 12 seconds?can anyone please answer?
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Nazima is fly fishing in a stream the tip of her fishing rod is 1.8 metre above the surface of the water And the fly at the end of the string rests On The Water 3.6 metre away and 2.4 away from a point directly under the tip of the rod as assuming that her string from the tip of her rod to the fly is taut how much string does she have out? if she pulls in the string at the rate 5cm per second what will be the horizontal distance of the fly from her after 12 seconds?can anyone please answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Nazima is fly fishing in a stream the tip of her fishing rod is 1.8 metre above the surface of the water And the fly at the end of the string rests On The Water 3.6 metre away and 2.4 away from a point directly under the tip of the rod as assuming that her string from the tip of her rod to the fly is taut how much string does she have out? if she pulls in the string at the rate 5cm per second what will be the horizontal distance of the fly from her after 12 seconds?can anyone please answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Nazima is fly fishing in a stream the tip of her fishing rod is 1.8 metre above the surface of the water And the fly at the end of the string rests On The Water 3.6 metre away and 2.4 away from a point directly under the tip of the rod as assuming that her string from the tip of her rod to the fly is taut how much string does she have out? if she pulls in the string at the rate 5cm per second what will be the horizontal distance of the fly from her after 12 seconds?can anyone please answer?.
Nazima is fly fishing in a stream the tip of her fishing rod is 1.8 metre above the surface of the water And the fly at the end of the string rests On The Water 3.6 metre away and 2.4 away from a point directly under the tip of the rod as assuming that her string from the tip of her rod to the fly is taut how much string does she have out? if she pulls in the string at the rate 5cm per second what will be the horizontal distance of the fly from her after 12 seconds?can anyone please answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Nazima is fly fishing in a stream the tip of her fishing rod is 1.8 metre above the surface of the water And the fly at the end of the string rests On The Water 3.6 metre away and 2.4 away from a point directly under the tip of the rod as assuming that her string from the tip of her rod to the fly is taut how much string does she have out? if she pulls in the string at the rate 5cm per second what will be the horizontal distance of the fly from her after 12 seconds?can anyone please answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Nazima is fly fishing in a stream the tip of her fishing rod is 1.8 metre above the surface of the water And the fly at the end of the string rests On The Water 3.6 metre away and 2.4 away from a point directly under the tip of the rod as assuming that her string from the tip of her rod to the fly is taut how much string does she have out? if she pulls in the string at the rate 5cm per second what will be the horizontal distance of the fly from her after 12 seconds?can anyone please answer?.
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