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A bomb is dropped from an aircraft when it is directly above the target at the height of 1000 m.The aircraft is moving with the horizontal velocity of 500 kilometre per hour. By how much distance will the bomb was the target? g is equal to 9.8 metre per second square?
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Calculating the Distance to the Target
To calculate the distance the bomb will travel before hitting the target, we need to consider the motion of the aircraft and the motion of the bomb after it is dropped.
Initial Vertical Velocity of the Bomb
The initial vertical velocity of the bomb when it is dropped can be calculated using the formula:
\[ v_{i} = \sqrt{2gh} \]
where \( v_{i} \) is the initial vertical velocity, \( g = 9.8 \, m/s^{2} \) is the acceleration due to gravity, and \( h = 1000 \, m \) is the height from which the bomb is dropped.
Time taken to reach the ground
The time taken for the bomb to reach the ground can be calculated using the formula:
\[ t = \sqrt{\frac{2h}{g}} \]
Horizontal Distance traveled by the aircraft
The horizontal distance traveled by the aircraft can be calculated using the formula:
\[ d = vt \]
where \( v = 500 \, km/h \) is the horizontal velocity of the aircraft converted to m/s, and \( t \) is the time taken for the bomb to reach the ground.
Final Calculation
Finally, the horizontal distance the bomb will travel before hitting the target can be calculated by summing up the horizontal distance traveled by the aircraft and the additional horizontal distance covered by the bomb due to its initial velocity.
By plugging in the values and carrying out the calculations, we can determine the exact distance the bomb will travel before hitting the target.
To calculate the distance the bomb will travel before hitting the target, we need to consider the motion of the aircraft and the motion of the bomb after it is dropped.
Initial Vertical Velocity of the Bomb
The initial vertical velocity of the bomb when it is dropped can be calculated using the formula:
\[ v_{i} = \sqrt{2gh} \]
where \( v_{i} \) is the initial vertical velocity, \( g = 9.8 \, m/s^{2} \) is the acceleration due to gravity, and \( h = 1000 \, m \) is the height from which the bomb is dropped.
Time taken to reach the ground
The time taken for the bomb to reach the ground can be calculated using the formula:
\[ t = \sqrt{\frac{2h}{g}} \]
Horizontal Distance traveled by the aircraft
The horizontal distance traveled by the aircraft can be calculated using the formula:
\[ d = vt \]
where \( v = 500 \, km/h \) is the horizontal velocity of the aircraft converted to m/s, and \( t \) is the time taken for the bomb to reach the ground.
Final Calculation
Finally, the horizontal distance the bomb will travel before hitting the target can be calculated by summing up the horizontal distance traveled by the aircraft and the additional horizontal distance covered by the bomb due to its initial velocity.
By plugging in the values and carrying out the calculations, we can determine the exact distance the bomb will travel before hitting the target.
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A bomb is dropped from an aircraft when it is directly above the target at the height of 1000 m.The aircraft is moving with the horizontal velocity of 500 kilometre per hour. By how much distance will the bomb was the target? g is equal to 9.8 metre per second square?
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A bomb is dropped from an aircraft when it is directly above the target at the height of 1000 m.The aircraft is moving with the horizontal velocity of 500 kilometre per hour. By how much distance will the bomb was the target? g is equal to 9.8 metre per second square? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A bomb is dropped from an aircraft when it is directly above the target at the height of 1000 m.The aircraft is moving with the horizontal velocity of 500 kilometre per hour. By how much distance will the bomb was the target? g is equal to 9.8 metre per second square? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bomb is dropped from an aircraft when it is directly above the target at the height of 1000 m.The aircraft is moving with the horizontal velocity of 500 kilometre per hour. By how much distance will the bomb was the target? g is equal to 9.8 metre per second square?.
A bomb is dropped from an aircraft when it is directly above the target at the height of 1000 m.The aircraft is moving with the horizontal velocity of 500 kilometre per hour. By how much distance will the bomb was the target? g is equal to 9.8 metre per second square? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A bomb is dropped from an aircraft when it is directly above the target at the height of 1000 m.The aircraft is moving with the horizontal velocity of 500 kilometre per hour. By how much distance will the bomb was the target? g is equal to 9.8 metre per second square? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bomb is dropped from an aircraft when it is directly above the target at the height of 1000 m.The aircraft is moving with the horizontal velocity of 500 kilometre per hour. By how much distance will the bomb was the target? g is equal to 9.8 metre per second square?.
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