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A pHelectrode obeys Nernst equation and is being operated at 25oC. The change in the open circuit voltage in millivolts across the electrode for a pH change from 6 to 8 is ___________.
(Important - Enter only the numerical value in the answer)
Correct answer is '118'. Can you explain this answer?
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A pHelectrode obeys Nernst equation and is being operated at 25oC. The...
The potential (E) of the PH electrode may be written by means of Nernst equation as
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A pHelectrode obeys Nernst equation and is being operated at 25oC. The...
The Nernst equation is a fundamental equation in electrochemistry that relates the voltage of an electrochemical cell to the activities (concentrations) of the species involved in the cell reaction. In the case of a pHelectrode, the Nernst equation can be written as:
E = E° - (0.0592/n) * log[H+]
where E is the electrode potential, E° is the standard electrode potential, [H+] is the hydrogen ion concentration (pH), and n is the number of electrons involved in the electrode reaction.
In this problem, we are given that the pH changes from 6 to 8. To calculate the change in open-circuit voltage, we need to find the difference in electrode potentials between pH 6 and pH 8.
Let's calculate the electrode potentials at pH 6 and pH 8 using the Nernst equation:
At pH 6:
E1 = E° - (0.0592/n) * log[H+]
= E° - (0.0592/n) * log(10^-6)
= E° - (0.0592/n) * (-6)
= E° + (0.0592/n) * 6
At pH 8:
E2 = E° - (0.0592/n) * log[H+]
= E° - (0.0592/n) * log(10^-8)
= E° - (0.0592/n) * (-8)
= E° + (0.0592/n) * 8
The change in open-circuit voltage is given by the difference between E2 and E1:
Change in open-circuit voltage = E2 - E1
= (E° + (0.0592/n) * 8) - (E° + (0.0592/n) * 6)
= (0.0592/n) * (8 - 6)
= (0.0592/n) * 2
= 0.118/n
Since we are not given the value of n, we cannot calculate the exact change in open-circuit voltage. However, if we assume n = 1 (which is often the case for a pHelectrode), we can calculate the change in open-circuit voltage:
Change in open-circuit voltage = 0.118/1
= 0.118 V
= 118 mV
Therefore, the change in open-circuit voltage across the electrode for a pH change from 6 to 8 is 118 millivolts.
E = E° - (0.0592/n) * log[H+]
where E is the electrode potential, E° is the standard electrode potential, [H+] is the hydrogen ion concentration (pH), and n is the number of electrons involved in the electrode reaction.
In this problem, we are given that the pH changes from 6 to 8. To calculate the change in open-circuit voltage, we need to find the difference in electrode potentials between pH 6 and pH 8.
Let's calculate the electrode potentials at pH 6 and pH 8 using the Nernst equation:
At pH 6:
E1 = E° - (0.0592/n) * log[H+]
= E° - (0.0592/n) * log(10^-6)
= E° - (0.0592/n) * (-6)
= E° + (0.0592/n) * 6
At pH 8:
E2 = E° - (0.0592/n) * log[H+]
= E° - (0.0592/n) * log(10^-8)
= E° - (0.0592/n) * (-8)
= E° + (0.0592/n) * 8
The change in open-circuit voltage is given by the difference between E2 and E1:
Change in open-circuit voltage = E2 - E1
= (E° + (0.0592/n) * 8) - (E° + (0.0592/n) * 6)
= (0.0592/n) * (8 - 6)
= (0.0592/n) * 2
= 0.118/n
Since we are not given the value of n, we cannot calculate the exact change in open-circuit voltage. However, if we assume n = 1 (which is often the case for a pHelectrode), we can calculate the change in open-circuit voltage:
Change in open-circuit voltage = 0.118/1
= 0.118 V
= 118 mV
Therefore, the change in open-circuit voltage across the electrode for a pH change from 6 to 8 is 118 millivolts.
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A pHelectrode obeys Nernst equation and is being operated at 25oC. The change in the opencircuit voltage in millivolts across the electrode for a pH change from 6 to 8 is ___________.(Important - Enter only the numerical value in the answer)Correct answer is '118'. Can you explain this answer?
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A pHelectrode obeys Nernst equation and is being operated at 25oC. The change in the opencircuit voltage in millivolts across the electrode for a pH change from 6 to 8 is ___________.(Important - Enter only the numerical value in the answer)Correct answer is '118'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A pHelectrode obeys Nernst equation and is being operated at 25oC. The change in the opencircuit voltage in millivolts across the electrode for a pH change from 6 to 8 is ___________.(Important - Enter only the numerical value in the answer)Correct answer is '118'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pHelectrode obeys Nernst equation and is being operated at 25oC. The change in the opencircuit voltage in millivolts across the electrode for a pH change from 6 to 8 is ___________.(Important - Enter only the numerical value in the answer)Correct answer is '118'. Can you explain this answer?.
A pHelectrode obeys Nernst equation and is being operated at 25oC. The change in the opencircuit voltage in millivolts across the electrode for a pH change from 6 to 8 is ___________.(Important - Enter only the numerical value in the answer)Correct answer is '118'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A pHelectrode obeys Nernst equation and is being operated at 25oC. The change in the opencircuit voltage in millivolts across the electrode for a pH change from 6 to 8 is ___________.(Important - Enter only the numerical value in the answer)Correct answer is '118'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pHelectrode obeys Nernst equation and is being operated at 25oC. The change in the opencircuit voltage in millivolts across the electrode for a pH change from 6 to 8 is ___________.(Important - Enter only the numerical value in the answer)Correct answer is '118'. Can you explain this answer?.
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