A body takes 4 minutes to cool from 100•C to 70•C . If the room temperature is 15•C then how many minutes will it need to cool from 70•C to 40• C - (1) 4 (2) 5 (3) 6 (4) 7?

Question

Answer

Solution:

Given, initial temperature of the body = 100°C
Final temperature of the body = 70°C
Time taken to cool from 100°C to 70°C = 4 minutes

Let us assume that the rate of cooling of the body is constant.

From the given data, we can find the rate of cooling of the body as follows:

Rate of cooling = (Initial temperature - Final temperature) / Time taken
= (100°C - 70°C) / 4 minutes
= 7.5°C/minute

Now, we need to find the time taken by the body to cool from 70°C to 40°C.

Let t be the time taken to cool from 70°C to 40°C.

Then, we can write:

Final temperature = Initial temperature - Rate of cooling × Time taken

Substituting the values, we get:

40°C = 70°C - 7.5°C/minute × t

Solving for t, we get:

t = (70°C - 40°C) / 7.5°C/minute
= 30/7.5
= 4

Therefore, the body will take 4 minutes to cool from 70°C to 40°C.

Hence, the answer is (1) 4.

Note: The solution is explained in HTML bullet points as follows:

Given:
- Initial temperature of the body = 100°C
- Final temperature of the body = 70°C
- Time taken to cool from 100°C to 70°C = 4 minutes
- Room temperature = 15°C

To find:
- Time taken by the body to cool from 70°C to 40°C

Solution:
- Find the rate of cooling of the body
- Use the rate of cooling to find the time taken to cool from 70°C to 40°C
- Substitute the values and solve for t
- The answer is (1) 4.

Answer

Answer

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