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In a hypothetical reaction
A(aq) 2B(aq) + C(aq) (1st order decomposition)
'A' is optically active (dextro-rototory) while 'B' and 'C' are optically inactive but 'B' takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.
In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:
In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:
- a)60 ml
- b)75 ml
- c)52.5 ml
- d)90 ml
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decompositi...
As only A is optically active. So concentration of A at t = 20 min ∝ 40° While concentration of A at t = 50 min ∝ 10°, so t1/2 = 15 min.
So volume consumed of H2O2 at t = 15 min = t1/2 , is according to 50% production of B at t = 60 min. production of B = 94.75% (four half lives)
So volume consumed
= 75 ml Ans.
So volume consumed of H2O2 at t = 15 min = t1/2 , is according to 50% production of B at t = 60 min. production of B = 94.75% (four half lives)
So volume consumed
= 75 ml Ans.
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In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer?
Question Description
In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer?.
In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer?.
Solutions for In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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Here you can find the meaning of In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a hypothetical reactionA(aq) 2B(aq) + C(aq) (1st order decomposition)A is optically active (dextro-rototory) while B and C are optically inactive but B takes part in a titration reaction (fast reaction) with H2O2. Hence the progress of reaction can be monitored by measuring rotation of plane of plane polarised light or by measuring volume of H2O2 consumed in titration.In an experiment the optical rotation was found to be θ = 40° at t = 20 min and θ = 10° at t = 50 min. from start of the reaction. If the progress would have been monitored by titration method, volume of H2O2 consumed at t = 15 min. (from start) is 40 ml then volume of H2O2 consumed at t = 60 min will be:a)60 mlb)75 mlc)52.5 mld)90 mlCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
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