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Methyl benzene can be prepared by reacting benzene with bromo-methane in the presence of
- a)Anhydrous AlCl3
- b)Br2/CCl4
- c)Ni/H2, 70oC
- d)Dil. H2SO4
Correct answer is option 'A'. Can you explain this answer?
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Methyl benzene can be prepared by reacting benzene with bromo-methane ...
Preparation of Methyl Benzene
The preparation of Methyl Benzene can be done by reacting Benzene with Bromo-Methane in the presence of Anhydrous AlCl3. This reaction is also known as Friedel-Crafts alkylation.
Reaction
CH3Br + C6H6 → CH3C6H5 + HBr
Mechanism
- The reaction takes place in the presence of Lewis Acid Catalyst, Anhydrous AlCl3.
- The Lewis Acid Catalyst AlCl3 accepts an electron pair from the Bromine atom in Bromo-Methane.
- The Bromine atom becomes positively charged and attacks the Benzene ring to form an intermediate carbocation.
- The intermediate carbocation is stabilized by the resonance of the Benzene ring.
- A Chloride ion from AlCl3 removes a proton from the intermediate carbocation to form Methyl Benzene.
- The Chloride ion from AlCl3 also regenerates the Lewis Acid Catalyst for further reaction.
Advantages
- This method is a simple and economical way of preparing Methyl Benzene.
- Anhydrous AlCl3 is a cheap catalyst and can be easily obtained.
- This method is useful for preparing Methyl Benzene in large quantities.
Disadvantages
- This method is not useful for preparing Methyl Benzene in small quantities as the reaction is highly exothermic and can lead to explosions.
- The use of Anhydrous AlCl3 can lead to the formation of toxic fumes which can be harmful to the environment and human health.
- This method is not useful for preparing Methyl Benzene with other substituents on the Benzene ring as the reaction can lead to the formation of unwanted by-products.
The preparation of Methyl Benzene can be done by reacting Benzene with Bromo-Methane in the presence of Anhydrous AlCl3. This reaction is also known as Friedel-Crafts alkylation.
Reaction
CH3Br + C6H6 → CH3C6H5 + HBr
Mechanism
- The reaction takes place in the presence of Lewis Acid Catalyst, Anhydrous AlCl3.
- The Lewis Acid Catalyst AlCl3 accepts an electron pair from the Bromine atom in Bromo-Methane.
- The Bromine atom becomes positively charged and attacks the Benzene ring to form an intermediate carbocation.
- The intermediate carbocation is stabilized by the resonance of the Benzene ring.
- A Chloride ion from AlCl3 removes a proton from the intermediate carbocation to form Methyl Benzene.
- The Chloride ion from AlCl3 also regenerates the Lewis Acid Catalyst for further reaction.
Advantages
- This method is a simple and economical way of preparing Methyl Benzene.
- Anhydrous AlCl3 is a cheap catalyst and can be easily obtained.
- This method is useful for preparing Methyl Benzene in large quantities.
Disadvantages
- This method is not useful for preparing Methyl Benzene in small quantities as the reaction is highly exothermic and can lead to explosions.
- The use of Anhydrous AlCl3 can lead to the formation of toxic fumes which can be harmful to the environment and human health.
- This method is not useful for preparing Methyl Benzene with other substituents on the Benzene ring as the reaction can lead to the formation of unwanted by-products.
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Methyl benzene can be prepared by reacting benzene with bromo-methane in the presence ofa)Anhydrous AlCl3b)Br2/CCl4c)Ni/H2, 70oCd)Dil. H2SO4Correct answer is option 'A'. Can you explain this answer?
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