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An electron is moving with velocity 6.6×10 raise to the power 3 metre per second the de Broglie wavelength associated with the electron is?
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An electron is moving with velocity 6.6×10 raise to the power 3 metre ...
10^-7 m hoga ans iska de broglie wavelength ka formula put karo lamda = h/p aur solve kar lo
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An electron is moving with velocity 6.6×10 raise to the power 3 metre ...
Calculating de Broglie Wavelength of an Electron
The de Broglie wavelength associated with a moving electron can be calculated using the de Broglie wavelength formula:
λ = h / p
where λ is the de Broglie wavelength, h is the Planck constant (6.626 x 10^-34 Js), and p is the momentum of the electron.
Calculating Momentum of the Electron
The momentum of the electron can be calculated using the formula:
p = m * v
where p is the momentum, m is the mass of the electron (9.11 x 10^-31 kg), and v is the velocity of the electron.
Substitute Values into the Formulas
Given:
- Velocity (v) = 6.6 x 10^3 m/s
- Mass of electron (m) = 9.11 x 10^-31 kg
- Planck constant (h) = 6.626 x 10^-34 Js
Calculate the momentum of the electron:
p = (9.11 x 10^-31 kg) * (6.6 x 10^3 m/s)
Calculate the de Broglie Wavelength
Substitute the momentum value into the de Broglie wavelength formula:
λ = (6.626 x 10^-34 Js) / p
Finally, calculate the de Broglie wavelength associated with the electron using the momentum calculated above.
This detailed calculation will help you determine the de Broglie wavelength associated with an electron moving at a velocity of 6.6 x 10^3 m/s.
The de Broglie wavelength associated with a moving electron can be calculated using the de Broglie wavelength formula:
λ = h / p
where λ is the de Broglie wavelength, h is the Planck constant (6.626 x 10^-34 Js), and p is the momentum of the electron.
Calculating Momentum of the Electron
The momentum of the electron can be calculated using the formula:
p = m * v
where p is the momentum, m is the mass of the electron (9.11 x 10^-31 kg), and v is the velocity of the electron.
Substitute Values into the Formulas
Given:
- Velocity (v) = 6.6 x 10^3 m/s
- Mass of electron (m) = 9.11 x 10^-31 kg
- Planck constant (h) = 6.626 x 10^-34 Js
Calculate the momentum of the electron:
p = (9.11 x 10^-31 kg) * (6.6 x 10^3 m/s)
Calculate the de Broglie Wavelength
Substitute the momentum value into the de Broglie wavelength formula:
λ = (6.626 x 10^-34 Js) / p
Finally, calculate the de Broglie wavelength associated with the electron using the momentum calculated above.
This detailed calculation will help you determine the de Broglie wavelength associated with an electron moving at a velocity of 6.6 x 10^3 m/s.
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An electron is moving with velocity 6.6×10 raise to the power 3 metre per second the de Broglie wavelength associated with the electron is?
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An electron is moving with velocity 6.6×10 raise to the power 3 metre per second the de Broglie wavelength associated with the electron is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electron is moving with velocity 6.6×10 raise to the power 3 metre per second the de Broglie wavelength associated with the electron is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron is moving with velocity 6.6×10 raise to the power 3 metre per second the de Broglie wavelength associated with the electron is?.
An electron is moving with velocity 6.6×10 raise to the power 3 metre per second the de Broglie wavelength associated with the electron is? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electron is moving with velocity 6.6×10 raise to the power 3 metre per second the de Broglie wavelength associated with the electron is? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron is moving with velocity 6.6×10 raise to the power 3 metre per second the de Broglie wavelength associated with the electron is?.
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