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How many photons of wavelength lamda is equals to 6600 nm must strike a totally reflecting screen per second at normal incidence. So as to exert a force of 1 N?
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How many photons of wavelength lamda is equals to 6600 nm must strike ...
Calculating the Energy of a Photon
To answer this question, we first need to calculate the energy of a photon of wavelength λ. We can use the following equation to do this:
E = hc/λ
Where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the photon in meters.
Calculating the Number of Photons Needed
Once we know the energy of a single photon, we can use the following equation to calculate the number of photons needed to exert a force of 1 N:
N = F/E
Where N is the number of photons needed, F is the force (in Newtons), and E is the energy of a single photon (in Joules).
Putting it all Together
For a photon of wavelength λ = 6600 nm, we can calculate the energy as follows:
E = (6.626 x 10^-34 J.s)(3.00 x 10^8 m/s)/(6600 x 10^-9 m) = 3.01 x 10^-19 J
Using the equation above, we can then calculate the number of photons needed to exert a force of 1 N as:
N = 1/(3.01 x 10^-19 J) = 3.32 x 10^18 photons/second
Therefore, 3.32 x 10^18 photons with a wavelength of 6600 nm must strike the totally reflecting screen per second at normal incidence in order to exert a force of 1 N.
To answer this question, we first need to calculate the energy of a photon of wavelength λ. We can use the following equation to do this:
E = hc/λ
Where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J.s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the photon in meters.
Calculating the Number of Photons Needed
Once we know the energy of a single photon, we can use the following equation to calculate the number of photons needed to exert a force of 1 N:
N = F/E
Where N is the number of photons needed, F is the force (in Newtons), and E is the energy of a single photon (in Joules).
Putting it all Together
For a photon of wavelength λ = 6600 nm, we can calculate the energy as follows:
E = (6.626 x 10^-34 J.s)(3.00 x 10^8 m/s)/(6600 x 10^-9 m) = 3.01 x 10^-19 J
Using the equation above, we can then calculate the number of photons needed to exert a force of 1 N as:
N = 1/(3.01 x 10^-19 J) = 3.32 x 10^18 photons/second
Therefore, 3.32 x 10^18 photons with a wavelength of 6600 nm must strike the totally reflecting screen per second at normal incidence in order to exert a force of 1 N.
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How many photons of wavelength lamda is equals to 6600 nm must strike a totally reflecting screen per second at normal incidence. So as to exert a force of 1 N?
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How many photons of wavelength lamda is equals to 6600 nm must strike a totally reflecting screen per second at normal incidence. So as to exert a force of 1 N? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about How many photons of wavelength lamda is equals to 6600 nm must strike a totally reflecting screen per second at normal incidence. So as to exert a force of 1 N? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many photons of wavelength lamda is equals to 6600 nm must strike a totally reflecting screen per second at normal incidence. So as to exert a force of 1 N?.
How many photons of wavelength lamda is equals to 6600 nm must strike a totally reflecting screen per second at normal incidence. So as to exert a force of 1 N? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about How many photons of wavelength lamda is equals to 6600 nm must strike a totally reflecting screen per second at normal incidence. So as to exert a force of 1 N? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many photons of wavelength lamda is equals to 6600 nm must strike a totally reflecting screen per second at normal incidence. So as to exert a force of 1 N?.
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