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A machine gun is mounted on a 2000 kg car on a horizontal frictionless surface. At some instant the gun fires bullets of mass 10 gm with a velocity of 500 m/sec with respect to the car. The number of bullets fired per second is ten. The average thrust on the system is
- a)550 newton
- b)50 newton
- c)250 newton
- d)250 dyne
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A machine gun is mounted on a 2000 kg car on a horizontal frictionless...
Given data:
- Mass of car = 2000 kg
- Mass of bullet = 10 gm = 0.01 kg
- Velocity of bullet with respect to car = 500 m/sec
- Number of bullets fired per second = 10
To find: Average thrust on the system
Formula:
- Thrust = Force = Rate of change of momentum
- Rate of change of momentum = (mass of bullet x velocity of bullet) x number of bullets fired per second
Calculation:
- Mass of all bullets fired per second = mass of one bullet x number of bullets fired per second
= 0.01 kg x 10 = 0.1 kg
- Total momentum imparted to the bullets per second = mass of all bullets fired per second x velocity of bullet with respect to car
= 0.1 kg x 500 m/sec = 50 Ns
- Rate of change of momentum = Total momentum imparted to the bullets per second / Time taken to impart the momentum to the bullets per second
= Total momentum imparted to the bullets per second / 1 sec
= 50 Ns / 1 sec
= 50 N
Therefore, the average thrust on the system is 50 N. Hence, option B is the correct answer.
- Mass of car = 2000 kg
- Mass of bullet = 10 gm = 0.01 kg
- Velocity of bullet with respect to car = 500 m/sec
- Number of bullets fired per second = 10
To find: Average thrust on the system
Formula:
- Thrust = Force = Rate of change of momentum
- Rate of change of momentum = (mass of bullet x velocity of bullet) x number of bullets fired per second
Calculation:
- Mass of all bullets fired per second = mass of one bullet x number of bullets fired per second
= 0.01 kg x 10 = 0.1 kg
- Total momentum imparted to the bullets per second = mass of all bullets fired per second x velocity of bullet with respect to car
= 0.1 kg x 500 m/sec = 50 Ns
- Rate of change of momentum = Total momentum imparted to the bullets per second / Time taken to impart the momentum to the bullets per second
= Total momentum imparted to the bullets per second / 1 sec
= 50 Ns / 1 sec
= 50 N
Therefore, the average thrust on the system is 50 N. Hence, option B is the correct answer.
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A machine gun is mounted on a 2000 kg car on a horizontal frictionless surface. At some instant the gun fires bullets of mass 10 gm with a velocity of 500 m/sec with respect to the car. The number of bullets fired per second is ten. The average thrust on the system isa)550 newtonb)50 newtonc)250 newtond)250 dyneCorrect answer is option 'B'. Can you explain this answer?
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