X-rays of wavelength 0.24 nm are Compton scattered and the scattered b...
° relative to the incident beam. The scattered beam has a wavelength of 0.33 nm. Calculate the energy of the incident X-ray and the energy of the scattered X-ray.
We can use the Compton scattering formula to solve this problem:
λ' - λ = h/mc(1 - cosθ)
where λ is the wavelength of the incident X-ray, λ' is the wavelength of the scattered X-ray, h is Planck's constant, m is the mass of the electron, c is the speed of light, and θ is the scattering angle.
First, we can calculate the change in wavelength:
λ' - λ = 0.33 nm - 0.28 nm = 0.05 nm
Next, we can plug in the values for the constants and scattering angle:
0.05 nm = (6.626 x 10^-34 J s)/(9.109 x 10^-31 kg)(3 x 10^8 m/s)(1 - cos60°)
Solving for λ gives:
λ = 0.28 nm
So the incident X-ray had a wavelength of 0.28 nm.
To find the energy of the incident X-ray, we can use the formula:
E = hc/λ
where E is the energy of the X-ray.
Plugging in the values:
E = (6.626 x 10^-34 J s)(3 x 10^8 m/s)/(0.28 x 10^-9 m)
E = 7.1 x 10^-15 J
So the energy of the incident X-ray is 7.1 x 10^-15 J.
To find the energy of the scattered X-ray, we can use the same formula with the new wavelength:
E' = hc/λ'
Plugging in the values:
E' = (6.626 x 10^-34 J s)(3 x 10^8 m/s)/(0.33 x 10^-9 m)
E' = 6.0 x 10^-15 J
So the energy of the scattered X-ray is 6.0 x 10^-15 J.