Given:
Density of ice = 0.92 gm/cm3
Density of sea water = 1.03 g/cm3

To Find:
Percentage of the iceberg below the surface of water.

Solution:

Step 1: Understanding the Concept
In order to understand why a part of the iceberg is below the surface of water, we need to understand the concept of buoyancy. According to Archimedes' principle, any object partially or completely submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid displaced by the object. This buoyant force helps objects float in a fluid.

Step 2: Applying the Concept
In the case of an iceberg, a significant portion of its mass is below the surface of the water due to its density being less than that of sea water. Let's assume the iceberg has a volume of 100 cm3.

Step 3: Calculation
1. Mass of the iceberg = Density × Volume = 0.92 g/cm3 × 100 cm3 = 92 g
2. The buoyant force acting on the iceberg is equal to the weight of the water displaced by the iceberg.
Buoyant force = Density of sea water × Volume of submerged part of the iceberg
Let the volume of the submerged part be V cm3.
Buoyant force = 1.03 g/cm3 × V cm3
3. Since the iceberg is in equilibrium, the weight of the iceberg is balanced by the buoyant force.
Weight of the iceberg = Mass of the iceberg × Acceleration due to gravity = 92 g × 9.8 m/s2 = 901.6 N
Buoyant force = Weight of the iceberg = 901.6 N
Therefore, 1.03 g/cm3 × V cm3 = 901.6 N
4. Solving for V:
V = 901.6 N / (1.03 g/cm3) = 875.34 cm3
5. Percentage of the iceberg below the surface of water:
Percentage = (Volume of submerged part / Total volume) × 100
= (875.34 cm3 / 100 cm3) × 100
= 875.34%

Step 4: Rounding off the Answer
Rounding off the percentage to the nearest whole number, we get:
Percentage = 89%

Therefore, approximately 89% of the iceberg will be below the surface of the water.