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A bacteria divide after every 35 min if culture containing 10^5 cell /ml is grown then cell concentration/ml after 175 min will be a)175*10^5 b)115*10^5 c)48*10^5 d)32*10^5?
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A bacteria divide after every 35 min if culture containing 10^5 cell /...
**Problem Statement:**

A bacteria divide after every 35 min. If a culture containing 10^5 cells/ml is grown, what will be the cell concentration/ml after 175 min?

**Solution:**

To solve this problem, we need to understand the concept of bacterial growth and the rate at which bacteria divide.

**Bacterial Growth:**

Bacterial growth can be divided into four phases: lag phase, exponential phase, stationary phase, and death phase. In the exponential phase, bacteria multiply rapidly and the population doubles after every division.

**Doubling Time:**

The doubling time of a population is the time it takes for the population size to double. In this case, the doubling time is 35 min.

**Calculation:**

Given that the initial cell concentration is 10^5 cells/ml, we need to calculate the cell concentration after 175 min.

To do this, we can use the formula for exponential growth:

N = N0 * 2^(t/d)

where:
- N is the final cell concentration
- N0 is the initial cell concentration
- t is the time in minutes
- d is the doubling time

Substituting the given values into the formula:

N = 10^5 * 2^(175/35)

Simplifying the equation:

N = 10^5 * 2^5

N = 10^5 * 32

N = 3.2 * 10^6 cells/ml

Therefore, the cell concentration after 175 min will be 3.2 * 10^6 cells/ml.

**Answer:**

The cell concentration/ml after 175 min will be d)32*10^5.
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A bacteria divide after every 35 min if culture containing 10^5 cell /ml is grown then cell concentration/ml after 175 min will be a)175*10^5 b)115*10^5 c)48*10^5 d)32*10^5?
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