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The dispersion law for a certain type of wave motion is ω= (c2k2 + m2)1/2 whereωis the angular frequency,kis the magnitude of the propagation vector andc,mare constants. The group velocity of these waves approaches :a)vg→ c as k→ ∞b)vg→ 0 as k→ ∞c)vg→ 0 as k→ 0d)vg→ c as k→ 0Correct answer is option 'A,C'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about The dispersion law for a certain type of wave motion is ω= (c2k2 + m2)1/2 whereωis the angular frequency,kis the magnitude of the propagation vector andc,mare constants. The group velocity of these waves approaches :a)vg→ c as k→ ∞b)vg→ 0 as k→ ∞c)vg→ 0 as k→ 0d)vg→ c as k→ 0Correct answer is option 'A,C'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The dispersion law for a certain type of wave motion is ω= (c2k2 + m2)1/2 whereωis the angular frequency,kis the magnitude of the propagation vector andc,mare constants. The group velocity of these waves approaches :a)vg→ c as k→ ∞b)vg→ 0 as k→ ∞c)vg→ 0 as k→ 0d)vg→ c as k→ 0Correct answer is option 'A,C'. Can you explain this answer?.

Solutions for The dispersion law for a certain type of wave motion is ω= (c2k2 + m2)1/2 whereωis the angular frequency,kis the magnitude of the propagation vector andc,mare constants. The group velocity of these waves approaches :a)vg→ c as k→ ∞b)vg→ 0 as k→ ∞c)vg→ 0 as k→ 0d)vg→ c as k→ 0Correct answer is option 'A,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics. Download more important topics, notes, lectures and mock test series for Physics Exam by signing up for free.

Here you can find the meaning of The dispersion law for a certain type of wave motion is ω= (c2k2 + m2)1/2 whereωis the angular frequency,kis the magnitude of the propagation vector andc,mare constants. The group velocity of these waves approaches :a)vg→ c as k→ ∞b)vg→ 0 as k→ ∞c)vg→ 0 as k→ 0d)vg→ c as k→ 0Correct answer is option 'A,C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The dispersion law for a certain type of wave motion is ω= (c2k2 + m2)1/2 whereωis the angular frequency,kis the magnitude of the propagation vector andc,mare constants. The group velocity of these waves approaches :a)vg→ c as k→ ∞b)vg→ 0 as k→ ∞c)vg→ 0 as k→ 0d)vg→ c as k→ 0Correct answer is option 'A,C'. Can you explain this answer?, a detailed solution for The dispersion law for a certain type of wave motion is ω= (c2k2 + m2)1/2 whereωis the angular frequency,kis the magnitude of the propagation vector andc,mare constants. The group velocity of these waves approaches :a)vg→ c as k→ ∞b)vg→ 0 as k→ ∞c)vg→ 0 as k→ 0d)vg→ c as k→ 0Correct answer is option 'A,C'. Can you explain this answer? has been provided alongside types of The dispersion law for a certain type of wave motion is ω= (c2k2 + m2)1/2 whereωis the angular frequency,kis the magnitude of the propagation vector andc,mare constants. The group velocity of these waves approaches :a)vg→ c as k→ ∞b)vg→ 0 as k→ ∞c)vg→ 0 as k→ 0d)vg→ c as k→ 0Correct answer is option 'A,C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The dispersion law for a certain type of wave motion is ω= (c2k2 + m2)1/2 whereωis the angular frequency,kis the magnitude of the propagation vector andc,mare constants. The group velocity of these waves approaches :a)vg→ c as k→ ∞b)vg→ 0 as k→ ∞c)vg→ 0 as k→ 0d)vg→ c as k→ 0Correct answer is option 'A,C'. Can you explain this answer? tests, examples and also practice Physics tests.