Two oxides of metal contain 27.6 and 30 oxygen respectively. If formula of first oxide is M3O4, then formula of second oxide is:a)MO2b)M2O3c)M2O5d)MOCorrect answer is option 'B'. Can you explain this answer?

Question

Answer

Explanation:

Formula of first oxide is M3O4. It means a metal (M) combines with 4 oxygen atoms to form an oxide.

So, the total number of oxygen atoms present in the first oxide = 4 x 3 = 12

Therefore, the total number of oxygen atoms present in the second oxide = 30 - 12 = 18

Let the formula of the second oxide be MOx

Since the metal combines with x oxygen atoms to form the second oxide, the formula can be written as MOx

Now, the total number of oxygen atoms present in MOx = x

So, we can write the equation as:

M3O4 + MOx = M3MoxO8

Substituting the values:

M3O4 + MOx = M3MoxO8

M3O4 + MOx = M3O8 + MoxO8

Since the two oxides have the same metal, we can equate the metal:

3M + M = M + 2M

4M = 3M + Mox

Mox = M

Therefore, the formula of the second oxide is M2O3.

Answer

Answer

Given that, the formula of first oxide is M3O4
Let mass of the metal = x
% of metal in M3O4=(3x/3x+64)×100

But as given percentage = (100-27.6) = 72.4 %
so, (3x/3x+64)×100=72.4 or x = 56.

In 2nd oxide,
oxygen = 30%....so metal = 70%
so, the ratio is
M : O = 70/56 : 30/16
=1.25: 1.875
=2 : 3
so, 2nd oxide is M2O3
Hence, the correct option is (B).

Answer

Answer

Two oxides of metal contain 27 and 30oxygrn respectively. if formula of first oxide is m3o4, then formula of second oxide is

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