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The relative velocity of air leaving a straight radial impeller of a centrifugal compressor is 100 m/s. If the impeller tip speed is 200 m/s, for a slip free operation, the absolute velocity (in m/s) at the impeller exit is _________ (accurate to one decimal place).  
Correct answer is '222.0 to 225.0'. Can you explain this answer?
Most Upvoted Answer
The relative velocity of air leaving a straight radial impeller of a c...
Given:
Relative velocity of air leaving the impeller, Vr = 100 m/s
Impeller tip speed, U = 200 m/s

To find:
The absolute velocity at the impeller exit.

Explanation:

The absolute velocity of the fluid at the exit of the impeller can be determined by considering the relative velocity and the impeller tip speed. The relationship between the absolute velocity, relative velocity, and impeller tip speed is given by the equation:

Vr = V - U

where V is the absolute velocity.

Substituting the given values:
100 = V - 200

Solving for V:
V = 100 + 200
V = 300 m/s

So, the absolute velocity at the impeller exit is 300 m/s.

However, the question asks for the slip-free operation.
In a slip-free operation, the relative velocity of the fluid leaving the impeller is equal to the impeller tip speed. Therefore, to achieve slip-free operation, the relative velocity should be equal to the impeller tip speed.

Substituting the given values:
100 = 200 - U

Solving for U:
U = 200 - 100
U = 100 m/s

So, for slip-free operation, the impeller tip speed should be 100 m/s.

Using the equation:
Vr = V - U

Substituting the given values:
100 = V - 100

Solving for V:
V = 100 + 100
V = 200 m/s

Therefore, for a slip-free operation, the absolute velocity at the impeller exit is 200 m/s.

Conclusion:
The correct answer is '200.0'.
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The relative velocity of air leaving a straight radial impeller of a centrifugal compressor is 100 m/s. If the impeller tip speed is 200 m/s, for a slip free operation, the absolute velocity (in m/s) at the impeller exit is _________ (accurate to one decimal place).Correct answer is '222.0 to 225.0'. Can you explain this answer?
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