Explanation:
The de Broglie wavelength of a particle is given by the formula:

λ = h/mv

where λ is the de Broglie wavelength, h is the Planck's constant, m is the mass of the particle, and v is the velocity of the particle.

The energy of a photon is given by the formula:

E = hc/λ

where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

Calculation:
Given, v = 2.2×10^8 m/s
Let λp be the wavelength of the photon and λd be the de Broglie wavelength of the particle.

Since λd = λp, we have:

h/mv = hc/λp

Solving for λp, we get:

λp = h/mvc

The ratio of kinetic energy of the particle to energy of the photon is given by:

(Kinetic energy of particle)/(Energy of photon) = (1/2)mv^2/(hc/λp)

Substituting the value of λp, we get:

(Kinetic energy of particle)/(Energy of photon) = (1/2)mv^2c/h

Substituting the given values, we get:

(Kinetic energy of particle)/(Energy of photon) = (1/2)×(mass of particle)×(velocity of particle)^2×c/h

(Kinetic energy of particle)/(Energy of photon) = (1/2)×(mass of particle)×(2.2×10^8)^2×3×10^8/6.626×10^-34

(Kinetic energy of particle)/(Energy of photon) = 1.34×10^10×(mass of particle)

Thus, the ratio of kinetic energy of the particle to energy of the photon is 1.34×10^10 times the mass of the particle.

Answer:
The ratio of kinetic energy of the particle to energy of the photon is 1.34×10^10 times the mass of the particle.