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A 50W,100V lamp is to be connected to an AC mains of 200 V , 50 Hz. What capacitance is essential to be put in series with the lamp? Ans- 9.2uF ( u= micro).?
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A 50W,100V lamp is to be connected to an AC mains of 200 V , 50 Hz. Wh...
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A 50W,100V lamp is to be connected to an AC mains of 200 V , 50 Hz. Wh...
Explanation:


Step 1: Calculate the Impedance of the Lamp


The first step in calculating the necessary capacitance is to find the impedance of the lamp. We can use the formula:

Z = V/I

Where Z is the impedance, V is the voltage, and I is the current. Since the lamp is rated at 50W and 100V, we can use the formula:

P = V^2/R

Where P is the power and R is the resistance. Solving for R, we get:

R = V^2/P

R = 100^2/50

R = 200 ohms

Now we can use the formula:

Z = sqrt(R^2 + Xc^2)

Where Xc is the capacitive reactance. Since we want to find the capacitance, we can rearrange this formula to solve for Xc:

Xc = sqrt(Z^2 - R^2)

Where Z is the impedance of the lamp, which we just calculated to be 200 ohms. Solving for Xc, we get:

Xc = sqrt(200^2 - 200^2)

Xc = 0 ohms

This means that the lamp has a purely resistive impedance and does not require any capacitance to be put in series with it.

Step 2: Re-calculate the Impedance of the Lamp


However, this calculation assumes that the lamp is being powered by a DC source. In reality, the lamp is being powered by an AC source, which means that it has an AC impedance. We can use the formula:

Xc = 1/(2*pi*f*C)

Where f is the frequency (50 Hz) and C is the capacitance we want to find. Solving for C, we get:

C = 1/(2*pi*f*Xc)

Where Xc is the capacitive reactance of the lamp, which we just calculated to be 0 ohms. Solving for C, we get:

C = infinity

This means that the lamp has an infinite capacitance, which is obviously not possible. The reason for this discrepancy is that the lamp has an inductance as well as a resistance, which means that its impedance is not purely resistive.

Step 3: Calculate the Required Capacitance


To account for the lamp's inductance, we need to find the lamp's total impedance. We can use the formula:

Z = sqrt(R^2 + (Xl - Xc)^2)

Where Xl is the inductive reactance. Since we don't know the inductance of the lamp, we can estimate it using the formula:

Xl = 2*pi*f*L

Where L is the inductance. Assuming a typical value of 0.1 Henry, we get:

Xl = 2*pi*50*0.1

Xl = 31.4 ohms

Now we can calculate the total impedance of the lamp:

Z = sqrt(200^2 + (31.4 - Xc)^2)

Solving for Xc, we get:

Xc = sqrt(Z^2 - R^2) - Xl

Xc = sqrt(200^2 - 200^2) - 31.4

Xc
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A 50W,100V lamp is to be connected to an AC mains of 200 V , 50 Hz. What capacitance is essential to be put in series with the lamp? Ans- 9.2uF ( u= micro).?
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