A 50W,100V lamp is to be connected to an AC mains of 200 V , 50 Hz. Wh...
Explanation:
Step 1: Calculate the Impedance of the Lamp
The first step in calculating the necessary capacitance is to find the impedance of the lamp. We can use the formula:
Z = V/I
Where Z is the impedance, V is the voltage, and I is the current. Since the lamp is rated at 50W and 100V, we can use the formula:
P = V^2/R
Where P is the power and R is the resistance. Solving for R, we get:
R = V^2/P
R = 100^2/50
R = 200 ohms
Now we can use the formula:
Z = sqrt(R^2 + Xc^2)
Where Xc is the capacitive reactance. Since we want to find the capacitance, we can rearrange this formula to solve for Xc:
Xc = sqrt(Z^2 - R^2)
Where Z is the impedance of the lamp, which we just calculated to be 200 ohms. Solving for Xc, we get:
Xc = sqrt(200^2 - 200^2)
Xc = 0 ohms
This means that the lamp has a purely resistive impedance and does not require any capacitance to be put in series with it.
Step 2: Re-calculate the Impedance of the Lamp
However, this calculation assumes that the lamp is being powered by a DC source. In reality, the lamp is being powered by an AC source, which means that it has an AC impedance. We can use the formula:
Xc = 1/(2*pi*f*C)
Where f is the frequency (50 Hz) and C is the capacitance we want to find. Solving for C, we get:
C = 1/(2*pi*f*Xc)
Where Xc is the capacitive reactance of the lamp, which we just calculated to be 0 ohms. Solving for C, we get:
C = infinity
This means that the lamp has an infinite capacitance, which is obviously not possible. The reason for this discrepancy is that the lamp has an inductance as well as a resistance, which means that its impedance is not purely resistive.
Step 3: Calculate the Required Capacitance
To account for the lamp's inductance, we need to find the lamp's total impedance. We can use the formula:
Z = sqrt(R^2 + (Xl - Xc)^2)
Where Xl is the inductive reactance. Since we don't know the inductance of the lamp, we can estimate it using the formula:
Xl = 2*pi*f*L
Where L is the inductance. Assuming a typical value of 0.1 Henry, we get:
Xl = 2*pi*50*0.1
Xl = 31.4 ohms
Now we can calculate the total impedance of the lamp:
Z = sqrt(200^2 + (31.4 - Xc)^2)
Solving for Xc, we get:
Xc = sqrt(Z^2 - R^2) - Xl
Xc = sqrt(200^2 - 200^2) - 31.4
Xc