Question Description
In a seriesLCRcircuit containing anACvoltage source of frequencyω, currentIand voltageV. Then for the given resistance, the correct statement is:a)Voltage acrossRis maximum atω2= 1/LCb)Current is maximum atω2= 1/LCc)Voltage acrossRis minimum atω2= 1/LCd)Current is minimum atω2= 1/LCCorrect answer is option 'B'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared
according to
the Physics exam syllabus. Information about In a seriesLCRcircuit containing anACvoltage source of frequencyω, currentIand voltageV. Then for the given resistance, the correct statement is:a)Voltage acrossRis maximum atω2= 1/LCb)Current is maximum atω2= 1/LCc)Voltage acrossRis minimum atω2= 1/LCd)Current is minimum atω2= 1/LCCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for In a seriesLCRcircuit containing anACvoltage source of frequencyω, currentIand voltageV. Then for the given resistance, the correct statement is:a)Voltage acrossRis maximum atω2= 1/LCb)Current is maximum atω2= 1/LCc)Voltage acrossRis minimum atω2= 1/LCd)Current is minimum atω2= 1/LCCorrect answer is option 'B'. Can you explain this answer?.
Solutions for In a seriesLCRcircuit containing anACvoltage source of frequencyω, currentIand voltageV. Then for the given resistance, the correct statement is:a)Voltage acrossRis maximum atω2= 1/LCb)Current is maximum atω2= 1/LCc)Voltage acrossRis minimum atω2= 1/LCd)Current is minimum atω2= 1/LCCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Physics.
Download more important topics, notes, lectures and mock test series for Physics Exam by signing up for free.
Here you can find the meaning of In a seriesLCRcircuit containing anACvoltage source of frequencyω, currentIand voltageV. Then for the given resistance, the correct statement is:a)Voltage acrossRis maximum atω2= 1/LCb)Current is maximum atω2= 1/LCc)Voltage acrossRis minimum atω2= 1/LCd)Current is minimum atω2= 1/LCCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In a seriesLCRcircuit containing anACvoltage source of frequencyω, currentIand voltageV. Then for the given resistance, the correct statement is:a)Voltage acrossRis maximum atω2= 1/LCb)Current is maximum atω2= 1/LCc)Voltage acrossRis minimum atω2= 1/LCd)Current is minimum atω2= 1/LCCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for In a seriesLCRcircuit containing anACvoltage source of frequencyω, currentIand voltageV. Then for the given resistance, the correct statement is:a)Voltage acrossRis maximum atω2= 1/LCb)Current is maximum atω2= 1/LCc)Voltage acrossRis minimum atω2= 1/LCd)Current is minimum atω2= 1/LCCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of In a seriesLCRcircuit containing anACvoltage source of frequencyω, currentIand voltageV. Then for the given resistance, the correct statement is:a)Voltage acrossRis maximum atω2= 1/LCb)Current is maximum atω2= 1/LCc)Voltage acrossRis minimum atω2= 1/LCd)Current is minimum atω2= 1/LCCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In a seriesLCRcircuit containing anACvoltage source of frequencyω, currentIand voltageV. Then for the given resistance, the correct statement is:a)Voltage acrossRis maximum atω2= 1/LCb)Current is maximum atω2= 1/LCc)Voltage acrossRis minimum atω2= 1/LCd)Current is minimum atω2= 1/LCCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Physics tests.