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A cord is wound round the circumference of a wheel of radius r. The axis of the wheel is horizontal and the moment of inertia about it is I. A weight mg is attached to the cord at the end. The weight falls from rest. After falling through a distance h, the angular velocity of the wheel will be
  • a)
    √2gh/I+mr
  • b)
    √2mgh/I+mr2
  • c)
    √2mgh/I+Mr2
  • d)
    √2gh
Correct answer is option 'B'. Can you explain this answer?
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A cord is wound round the circumference of a wheel of radius r. The ax...
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A cord is wound round the circumference of a wheel of radius r. The axis of the wheel is horizontal and the moment of inertia about it is I. A weight mg is attached to the cord at the end. The weight falls from rest. After falling through a distance h, the angular velocity of the wheel will bea)√2gh/I+mrb)√2mgh/I+mr2c)√2mgh/I+Mr2d)√2ghCorrect answer is option 'B'. Can you explain this answer?
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A cord is wound round the circumference of a wheel of radius r. The axis of the wheel is horizontal and the moment of inertia about it is I. A weight mg is attached to the cord at the end. The weight falls from rest. After falling through a distance h, the angular velocity of the wheel will bea)√2gh/I+mrb)√2mgh/I+mr2c)√2mgh/I+Mr2d)√2ghCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A cord is wound round the circumference of a wheel of radius r. The axis of the wheel is horizontal and the moment of inertia about it is I. A weight mg is attached to the cord at the end. The weight falls from rest. After falling through a distance h, the angular velocity of the wheel will bea)√2gh/I+mrb)√2mgh/I+mr2c)√2mgh/I+Mr2d)√2ghCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cord is wound round the circumference of a wheel of radius r. The axis of the wheel is horizontal and the moment of inertia about it is I. A weight mg is attached to the cord at the end. The weight falls from rest. After falling through a distance h, the angular velocity of the wheel will bea)√2gh/I+mrb)√2mgh/I+mr2c)√2mgh/I+Mr2d)√2ghCorrect answer is option 'B'. Can you explain this answer?.
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