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EMF of the cell Ni/Ni^2 //Cl^-/Cl2/Pt is.V if the SRP of nickel and chlorine electrodes are -0.25 V and 1.36 V respectively.?
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EMF of the cell Ni/Ni^2 //Cl^-/Cl2/Pt is.V if the SRP of nickel and ch...
Electrochemical Cell Overview
The given electrochemical cell is represented as Ni/Ni^2+ // Cl^-/Cl2/Pt. To find the electromotive force (EMF) of this cell, we use the standard reduction potentials (SRP) of the electrode reactions.
Standard Reduction Potentials
- The SRP of nickel (Ni) is -0.25 V.
- The SRP of chlorine (Cl2) is 1.36 V.
Cell Reaction and Half-Reactions
1. Anode Reaction (Oxidation):
- Nickel is oxidized: Ni → Ni^2+ + 2e^-
- This half-reaction has a SRP of -0.25 V.
2. Cathode Reaction (Reduction):
- Chlorine is reduced: Cl2 + 2e^- → 2Cl^-
- This half-reaction has a SRP of 1.36 V.
Calculating EMF of the Cell
The EMF of the cell can be calculated using the formula:
EMF = SRP(cathode) - SRP(anode)
Substituting the values:
- EMF = 1.36 V - (-0.25 V)
Final Calculation
- EMF = 1.36 V + 0.25 V
- EMF = 1.61 V
Conclusion
The EMF of the electrochemical cell Ni/Ni^2+ // Cl^-/Cl2/Pt is 1.61 V. This positive value indicates that the cell can perform work and drive the electrochemical reaction forward efficiently.
The given electrochemical cell is represented as Ni/Ni^2+ // Cl^-/Cl2/Pt. To find the electromotive force (EMF) of this cell, we use the standard reduction potentials (SRP) of the electrode reactions.
Standard Reduction Potentials
- The SRP of nickel (Ni) is -0.25 V.
- The SRP of chlorine (Cl2) is 1.36 V.
Cell Reaction and Half-Reactions
1. Anode Reaction (Oxidation):
- Nickel is oxidized: Ni → Ni^2+ + 2e^-
- This half-reaction has a SRP of -0.25 V.
2. Cathode Reaction (Reduction):
- Chlorine is reduced: Cl2 + 2e^- → 2Cl^-
- This half-reaction has a SRP of 1.36 V.
Calculating EMF of the Cell
The EMF of the cell can be calculated using the formula:
EMF = SRP(cathode) - SRP(anode)
Substituting the values:
- EMF = 1.36 V - (-0.25 V)
Final Calculation
- EMF = 1.36 V + 0.25 V
- EMF = 1.61 V
Conclusion
The EMF of the electrochemical cell Ni/Ni^2+ // Cl^-/Cl2/Pt is 1.61 V. This positive value indicates that the cell can perform work and drive the electrochemical reaction forward efficiently.
Community Answer
EMF of the cell Ni/Ni^2 //Cl^-/Cl2/Pt is.V if the SRP of nickel and ch...
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EMF of the cell Ni/Ni^2 //Cl^-/Cl2/Pt is.V if the SRP of nickel and chlorine electrodes are -0.25 V and 1.36 V respectively.?
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EMF of the cell Ni/Ni^2 //Cl^-/Cl2/Pt is.V if the SRP of nickel and chlorine electrodes are -0.25 V and 1.36 V respectively.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about EMF of the cell Ni/Ni^2 //Cl^-/Cl2/Pt is.V if the SRP of nickel and chlorine electrodes are -0.25 V and 1.36 V respectively.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for EMF of the cell Ni/Ni^2 //Cl^-/Cl2/Pt is.V if the SRP of nickel and chlorine electrodes are -0.25 V and 1.36 V respectively.?.
EMF of the cell Ni/Ni^2 //Cl^-/Cl2/Pt is.V if the SRP of nickel and chlorine electrodes are -0.25 V and 1.36 V respectively.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about EMF of the cell Ni/Ni^2 //Cl^-/Cl2/Pt is.V if the SRP of nickel and chlorine electrodes are -0.25 V and 1.36 V respectively.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for EMF of the cell Ni/Ni^2 //Cl^-/Cl2/Pt is.V if the SRP of nickel and chlorine electrodes are -0.25 V and 1.36 V respectively.?.
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