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In an electron gun, the electrons are accelerated by the potential V. If e is the charge and m is the mass of an electron, then the maximum velocity of these electrons will be
- a)2eV/m
- b)√2eV/m
- c)√2m/eV
- d)V2/2em
Correct answer is option 'B'. Can you explain this answer?
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In an electron gun, the electrons are accelerated by the potential V. ...
The maximum velocity of the electrons can be found using the principle of conservation of energy.
The potential energy gained by an electron when it is accelerated through a potential V is equal to the kinetic energy it acquires.
The potential energy gained by an electron is given by:
Potential energy = eV
The kinetic energy of an electron is given by:
Kinetic energy = (1/2)mv^2
Setting the potential energy equal to the kinetic energy:
eV = (1/2)mv^2
Simplifying and solving for v:
v^2 = (2eV)/m
v = sqrt((2eV)/m)
Therefore, the maximum velocity of the electrons is given by option a) 2eV/√m.
The potential energy gained by an electron when it is accelerated through a potential V is equal to the kinetic energy it acquires.
The potential energy gained by an electron is given by:
Potential energy = eV
The kinetic energy of an electron is given by:
Kinetic energy = (1/2)mv^2
Setting the potential energy equal to the kinetic energy:
eV = (1/2)mv^2
Simplifying and solving for v:
v^2 = (2eV)/m
v = sqrt((2eV)/m)
Therefore, the maximum velocity of the electrons is given by option a) 2eV/√m.
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In an electron gun, the electrons are accelerated by the potential V. If e is the charge and m is the mass of an electron, then the maximum velocity of these electrons will bea)2eV/mb)√2eV/mc)√2m/eVd)V2/2emCorrect answer is option 'B'. Can you explain this answer?
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