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A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.
Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.
Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.
The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.
Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.
Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.
The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.
Correct answer is '6957'. Can you explain this answer?
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Verified Answer
A waste to energy plant burns dry solid waste of composition : Carbon ...
Oxygen required for 350 tonne/day
(32/12) x 350 = 933.33
Oxygen required for 100 tonne/day
(32/4) x 100 = 800
Oxygen required for 60 tonne/day
(32/32) x 60 = 60
Oxygen required for 60 tonne/day
(32/14) x 30 = 68.57
Total O2 = 1861.9 tonne/day
Available O2 in waste = 260 tonne/day
Required = 1861.9 – 260 = 1601.9 tonne/day
Amount of air required = 1601.9/0.23 = 6964.78 tonne/day ≌ 6965 tonne/day
Most Upvoted Answer
A waste to energy plant burns dry solid waste of composition : Carbon ...
Given:
- Composition of dry solid waste: Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3%, and Inerts = 20%
- Burning rate: 1000 tonnes/d
- Oxygen in air by weight: 23%
- Atomic weights: H = 1, C = 12, N = 14, O = 16, S = 32
To find:
The stoichiometric (theoretical) amount of air required for complete burning of this waste in tonnes/d.
Solution:
To calculate the stoichiometric amount of air required, we need to determine the molar ratio between the waste components and the oxygen required for complete combustion.
Step 1: Calculate the molar ratios for each component:
- Carbon: The molar ratio of carbon to oxygen is 1:1, as carbon combusts to form carbon dioxide (CO2).
- Hydrogen: The molar ratio of hydrogen to oxygen is 1:0.5, as hydrogen combusts to form water (H2O).
- Sulphur: The molar ratio of sulphur to oxygen is 1:1, as sulphur combusts to form sulphur dioxide (SO2).
- Nitrogen: The molar ratio of nitrogen to oxygen is 1:2, as nitrogen combusts to form nitrogen dioxide (NO2).
Step 2: Calculate the oxygen required for each component:
To calculate the oxygen required, we multiply the molar ratio by the weight percentage of each component and divide by the atomic weight.
- Oxygen required for carbon: (35% * 1000 tonnes/d * 1/100 * 1 mol C/12 g C * 32 g O/1 mol CO2) = 933.33 tonnes/d
- Oxygen required for hydrogen: (10% * 1000 tonnes/d * 1/100 * 1 mol H/1 g H * 0.5 mol O/1 mol H2O * 16 g O/1 mol O2) = 80 tonnes/d
- Oxygen required for sulphur: (6% * 1000 tonnes/d * 1/100 * 1 mol S/32 g S * 1 mol O/1 mol SO2 * 32 g O/1 mol O2) = 30 tonnes/d
- Oxygen required for nitrogen: (3% * 1000 tonnes/d * 1/100 * 1 mol N/14 g N * 2 mol O/1 mol NO2 * 32 g O/1 mol O2) = 34.29 tonnes/d
Step 3: Calculate the total oxygen required:
The total oxygen required is the sum of the oxygen required for each component.
Total oxygen required = 933.33 tonnes/d + 80 tonnes/d + 30 tonnes/d + 34.29 tonnes/d = 1077.62 tonnes/d
Step 4: Calculate the stoichiometric amount of air:
The stoichiometric amount of air is the ratio of oxygen required to the weight percentage of oxygen in air.
Stoichiometric amount of air = (1077.62 tonnes/d) / (23% * 1000 tonnes/d)
- Composition of dry solid waste: Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3%, and Inerts = 20%
- Burning rate: 1000 tonnes/d
- Oxygen in air by weight: 23%
- Atomic weights: H = 1, C = 12, N = 14, O = 16, S = 32
To find:
The stoichiometric (theoretical) amount of air required for complete burning of this waste in tonnes/d.
Solution:
To calculate the stoichiometric amount of air required, we need to determine the molar ratio between the waste components and the oxygen required for complete combustion.
Step 1: Calculate the molar ratios for each component:
- Carbon: The molar ratio of carbon to oxygen is 1:1, as carbon combusts to form carbon dioxide (CO2).
- Hydrogen: The molar ratio of hydrogen to oxygen is 1:0.5, as hydrogen combusts to form water (H2O).
- Sulphur: The molar ratio of sulphur to oxygen is 1:1, as sulphur combusts to form sulphur dioxide (SO2).
- Nitrogen: The molar ratio of nitrogen to oxygen is 1:2, as nitrogen combusts to form nitrogen dioxide (NO2).
Step 2: Calculate the oxygen required for each component:
To calculate the oxygen required, we multiply the molar ratio by the weight percentage of each component and divide by the atomic weight.
- Oxygen required for carbon: (35% * 1000 tonnes/d * 1/100 * 1 mol C/12 g C * 32 g O/1 mol CO2) = 933.33 tonnes/d
- Oxygen required for hydrogen: (10% * 1000 tonnes/d * 1/100 * 1 mol H/1 g H * 0.5 mol O/1 mol H2O * 16 g O/1 mol O2) = 80 tonnes/d
- Oxygen required for sulphur: (6% * 1000 tonnes/d * 1/100 * 1 mol S/32 g S * 1 mol O/1 mol SO2 * 32 g O/1 mol O2) = 30 tonnes/d
- Oxygen required for nitrogen: (3% * 1000 tonnes/d * 1/100 * 1 mol N/14 g N * 2 mol O/1 mol NO2 * 32 g O/1 mol O2) = 34.29 tonnes/d
Step 3: Calculate the total oxygen required:
The total oxygen required is the sum of the oxygen required for each component.
Total oxygen required = 933.33 tonnes/d + 80 tonnes/d + 30 tonnes/d + 34.29 tonnes/d = 1077.62 tonnes/d
Step 4: Calculate the stoichiometric amount of air:
The stoichiometric amount of air is the ratio of oxygen required to the weight percentage of oxygen in air.
Stoichiometric amount of air = (1077.62 tonnes/d) / (23% * 1000 tonnes/d)
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A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer?
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A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer?.
A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer?.
Solutions for A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer?, a detailed solution for A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer? has been provided alongside types of A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A waste to energy plant burns dry solid waste of composition : Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%.Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to CO2. Hydrogen to H2O, Sulphur to SO2 and Nitrogen to NO2.Given Atomic weighs : H = 1, C = 12, N = 14, O = 16, S = 32.The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is __________.Correct answer is '6957'. Can you explain this answer? tests, examples and also practice GATE tests.
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