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The causal realization of a system transfer function H(s ) having poles at (2, –1), (–2, 1) and zeroes at (2, 1), (–2, –1) will be
- a)Unstable, complex, allpass
- b)Unstable, real, highpass
- c)Stable, complex, lowpass
- d)Stable, real, allpass
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The causal realization of a system transfer function H(s ) having pole...
Pole locations: (2, –1) and (–2, 1)
Zero locations: (2, 1) and (–2, 1)
Filter is all pass since for each pole, there is a mirror image zero.
System is unstable because for stability of causal system all poles should lie in the L.H.S. of s-plane and here one pole is lying in the R.H.S.
i.e. transfer function is complex.
Zero locations: (2, 1) and (–2, 1)
Filter is all pass since for each pole, there is a mirror image zero.
System is unstable because for stability of causal system all poles should lie in the L.H.S. of s-plane and here one pole is lying in the R.H.S.
i.e. transfer function is complex.
Most Upvoted Answer
The causal realization of a system transfer function H(s ) having pole...
The causal realization of a transfer function H(s) with poles at (2, -3) would involve using the factors corresponding to the poles to represent the transfer function.
In this case, the poles at (2, -3) would give rise to the factors (s - 2) and (s + 3) in the denominator of the transfer function. The numerator of the transfer function would depend on the specific function being realized.
To create a causal realization, we want to ensure that all poles are in the left half of the complex plane. In this case, since the poles are at (2, -3), both poles have negative real parts and are already in the left half plane, so no additional modifications are needed.
The causal realization of the transfer function H(s) would then involve using the factors (s - 2) and (s + 3) in the denominator, and potentially additional factors in the numerator, depending on the specific transfer function.
In this case, the poles at (2, -3) would give rise to the factors (s - 2) and (s + 3) in the denominator of the transfer function. The numerator of the transfer function would depend on the specific function being realized.
To create a causal realization, we want to ensure that all poles are in the left half of the complex plane. In this case, since the poles are at (2, -3), both poles have negative real parts and are already in the left half plane, so no additional modifications are needed.
The causal realization of the transfer function H(s) would then involve using the factors (s - 2) and (s + 3) in the denominator, and potentially additional factors in the numerator, depending on the specific transfer function.
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The causal realization of a system transfer function H(s ) having poles at (2, –1), (–2, 1) and zeroes at (2, 1), (–2, –1) will bea)Unstable, complex, allpassb)Unstable, real, highpassc)Stable, complex, lowpassd)Stable, real, allpassCorrect answer is option 'A'. Can you explain this answer?
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