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The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.?
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The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. ca...
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The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. ca...
Calculation of acceleration due to gravity of new Earth
Given:
Mass of Earth, M = 6×10^24 kg
Radius of Moon, R = 1.7×10^6 m
Formula:
Acceleration due to gravity, g = GM/R^2
Where G is the universal gravitational constant, M is the mass of the object and R is the distance between the centers of the two objects.
Calculation:
Let us assume that the new Earth has the same mass as the original Earth but with a radius equal to the radius of the Moon. In this case, the new distance between the centers of the two objects would be (3.74R) because the new Earth would have a radius that is 1/3.74 times the radius of the original Earth.
So, the acceleration due to gravity of the new Earth, g', can be calculated as:
g' = GM/(3.74R)^2
g' = (6.67×10^-11 Nm^2/kg^2) × (6×10^24 kg) / (3.74×1.7×10^6 m)^2
g' = 1.63 m/s^2
Therefore, the acceleration due to gravity of the new Earth would be 1.63 m/s^2. This is significantly less than the acceleration due to gravity on the surface of the original Earth, which is around 9.81 m/s^2.
Explanation:
The acceleration due to gravity is directly proportional to the mass of the object and inversely proportional to the square of the distance between the centers of the two objects. When the radius of the Earth is compressed to the size of the Moon, the distance between the centers of the two objects decreases significantly. This results in a decrease in the acceleration due to gravity of the new Earth.
Given:
Mass of Earth, M = 6×10^24 kg
Radius of Moon, R = 1.7×10^6 m
Formula:
Acceleration due to gravity, g = GM/R^2
Where G is the universal gravitational constant, M is the mass of the object and R is the distance between the centers of the two objects.
Calculation:
Let us assume that the new Earth has the same mass as the original Earth but with a radius equal to the radius of the Moon. In this case, the new distance between the centers of the two objects would be (3.74R) because the new Earth would have a radius that is 1/3.74 times the radius of the original Earth.
So, the acceleration due to gravity of the new Earth, g', can be calculated as:
g' = GM/(3.74R)^2
g' = (6.67×10^-11 Nm^2/kg^2) × (6×10^24 kg) / (3.74×1.7×10^6 m)^2
g' = 1.63 m/s^2
Therefore, the acceleration due to gravity of the new Earth would be 1.63 m/s^2. This is significantly less than the acceleration due to gravity on the surface of the original Earth, which is around 9.81 m/s^2.
Explanation:
The acceleration due to gravity is directly proportional to the mass of the object and inversely proportional to the square of the distance between the centers of the two objects. When the radius of the Earth is compressed to the size of the Moon, the distance between the centers of the two objects decreases significantly. This results in a decrease in the acceleration due to gravity of the new Earth.
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The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.?
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The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.?.
The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.?.
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The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.?, a detailed solution for The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.? has been provided alongside types of The mass of the earth is 6×10^24kg and radius of moon is 1.7×10^6m. calculate the acceleration due to gravity of new earth which is formed by the compression of the Earth equal to the size of the moon. Hint:g=GM/R^2 , g'=GM/(1/3.74R)^2.? theory, EduRev gives you an
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