NEET Exam > NEET Questions > Certain perfect gas is found to obey PV3/2= c...
Start Learning for Free
Certain perfect gas is found to obey PV3/2 = constant during an adiabatic process. If such a gas at initial temperature T is adiabatically compressed to half the initial volume, its final temperature will be
- a)√2 T
- b)2 T
- c)2√2 T
- d)4 T
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Certain perfect gas is found to obey PV3/2= constantduring an adiabati...
Community Answer
Certain perfect gas is found to obey PV3/2= constantduring an adiabati...
T/2
b) T
c) 2T
d) 4T
Given that PV^3/2 = constant for the gas during an adiabatic process, we have:
P1V1^3/2 = P2V2^3/2
Since the process is adiabatic, we have:
P1V1^γ = P2V2^γ
where γ is the ratio of specific heats for the gas.
Since the gas is being adiabatically compressed to half the initial volume, we have:
V2 = V1/2
Substitute this into the equation for the adiabatic process:
P1V1^γ = P2(V1/2)^γ
Solving for P2:
P2 = P1(1/2)^(3/γ) = P1(1/2)^(3/5)
Now, for an ideal gas, the pressure and temperature are directly proportional during an adiabatic process:
P1/T1 = P2/T2
Substitute the expressions for P2 and V2:
P1/T1 = P1(1/2)^(3/5) / T2
Solving for T2:
T2 = T1/(1/2)^(3/5) = T1/(2^3/5) = T1/(2^(3/5)) = T1/2^0.6
Therefore, the final temperature after adiabatic compression to half the initial volume will be T/2^(0.6) = T/2^0.6 = T/2^3/5 = T/2^(3/5) = T/2^(0.6) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T
b) T
c) 2T
d) 4T
Given that PV^3/2 = constant for the gas during an adiabatic process, we have:
P1V1^3/2 = P2V2^3/2
Since the process is adiabatic, we have:
P1V1^γ = P2V2^γ
where γ is the ratio of specific heats for the gas.
Since the gas is being adiabatically compressed to half the initial volume, we have:
V2 = V1/2
Substitute this into the equation for the adiabatic process:
P1V1^γ = P2(V1/2)^γ
Solving for P2:
P2 = P1(1/2)^(3/γ) = P1(1/2)^(3/5)
Now, for an ideal gas, the pressure and temperature are directly proportional during an adiabatic process:
P1/T1 = P2/T2
Substitute the expressions for P2 and V2:
P1/T1 = P1(1/2)^(3/5) / T2
Solving for T2:
T2 = T1/(1/2)^(3/5) = T1/(2^3/5) = T1/(2^(3/5)) = T1/2^0.6
Therefore, the final temperature after adiabatic compression to half the initial volume will be T/2^(0.6) = T/2^0.6 = T/2^3/5 = T/2^(3/5) = T/2^(0.6) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T/2^(3/5) = T
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer?
Question Description
Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer?.
Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Certain perfect gas is found to obey PV3/2= constantduring an adiabatic process. If such a gas at initialtemperature T is adiabatically compressed to half theinitial volume, its final temperature will bea)√2 Tb)2 Tc)2√2 Td)4 TCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup