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A single-phase, full-bridge, fully controlled thyristor rectifier feeds a load comprising a 10 Ω resistance in series with a very large inductance. The rectifier is fed from an ideal 230 V, 50 Hz sinusoidal source through cables which have negligible internal resistance and a total inductance of 2.28 mH. If the thyristors are triggered at an angle α = 45°, the commutation overlap angle in degree (rounded off to 2 decimal places) is_____.
Correct answer is '4.80'. Can you explain this answer?
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A single-phase, full-bridge, fully controlled thyristor rectifier feed...
1-φ, SCR bridge rectifier
α = 45°, R = 10 Ω
supply 230 V, 50 Hz
Ls = 2.28 mH
µ = ?
Find I0
I0(10 + 0.456) = 146.42
= 4 × 50 × 2.28 × 10–3 × 14 = 6.384
cos45° – cos(45° + µ) = 0.061659
45 + µ = 49.80
∴ µ = 4.80°
α = 45°, R = 10 Ω
supply 230 V, 50 Hz
Ls = 2.28 mH
µ = ?
Find I0
I0(10 + 0.456) = 146.42
= 4 × 50 × 2.28 × 10–3 × 14 = 6.384
cos45° – cos(45° + µ) = 0.061659
45 + µ = 49.80
∴ µ = 4.80°
Most Upvoted Answer
A single-phase, full-bridge, fully controlled thyristor rectifier feed...
KW, 220 V resistive load. The AC source voltage is 240 V (rms) at 50 Hz. The firing angle of the thyristors can be varied from 0° to 180°.
To determine the average output voltage and current of the rectifier, we need to first determine the conduction angle of the thyristors. This is given by:
α = π – cos⁻¹ (VL / VS)
Where VL is the load voltage (220 V) and VS is the source voltage (240 V). Plugging in the values, we get:
α = π – cos⁻¹ (220 / 240)
α = 31.4°
This means that the thyristors will start conducting at 31.4° after the zero-crossing of the AC voltage waveform.
Next, we need to determine the RMS value of the load current. This is given by:
IL(rms) = VL / R
Where R is the load resistance (220 V / 10 kW = 22 Ω). Plugging in the values, we get:
IL(rms) = 220 / 22
IL(rms) = 10 A
Now, we can determine the average output voltage and current of the rectifier using the following equations:
Vout(avg) = VS / π * (1 – cos α)
Iout(avg) = IL(rms) * cos α
Plugging in the values, we get:
Vout(avg) = 240 / π * (1 – cos 31.4°)
Vout(avg) = 156 V
Iout(avg) = 10 * cos 31.4°
Iout(avg) = 8.6 A
Therefore, the average output voltage of the rectifier is 156 V and the average output current is 8.6 A.
To determine the average output voltage and current of the rectifier, we need to first determine the conduction angle of the thyristors. This is given by:
α = π – cos⁻¹ (VL / VS)
Where VL is the load voltage (220 V) and VS is the source voltage (240 V). Plugging in the values, we get:
α = π – cos⁻¹ (220 / 240)
α = 31.4°
This means that the thyristors will start conducting at 31.4° after the zero-crossing of the AC voltage waveform.
Next, we need to determine the RMS value of the load current. This is given by:
IL(rms) = VL / R
Where R is the load resistance (220 V / 10 kW = 22 Ω). Plugging in the values, we get:
IL(rms) = 220 / 22
IL(rms) = 10 A
Now, we can determine the average output voltage and current of the rectifier using the following equations:
Vout(avg) = VS / π * (1 – cos α)
Iout(avg) = IL(rms) * cos α
Plugging in the values, we get:
Vout(avg) = 240 / π * (1 – cos 31.4°)
Vout(avg) = 156 V
Iout(avg) = 10 * cos 31.4°
Iout(avg) = 8.6 A
Therefore, the average output voltage of the rectifier is 156 V and the average output current is 8.6 A.
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A single-phase, full-bridge, fully controlled thyristor rectifier feeds a load comprising a 10 Ω resistance in series with a very large inductance. The rectifier is fed from an ideal 230 V, 50 Hz sinusoidal source through cables which have negligible internal resistance and a total inductance of 2.28 mH. If the thyristors are triggered at an angle α = 45°, the commutation overlap angle in degree (rounded off to 2 decimal places) is_____.Correct answer is '4.80'. Can you explain this answer?
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A single-phase, full-bridge, fully controlled thyristor rectifier feeds a load comprising a 10 Ω resistance in series with a very large inductance. The rectifier is fed from an ideal 230 V, 50 Hz sinusoidal source through cables which have negligible internal resistance and a total inductance of 2.28 mH. If the thyristors are triggered at an angle α = 45°, the commutation overlap angle in degree (rounded off to 2 decimal places) is_____.Correct answer is '4.80'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A single-phase, full-bridge, fully controlled thyristor rectifier feeds a load comprising a 10 Ω resistance in series with a very large inductance. The rectifier is fed from an ideal 230 V, 50 Hz sinusoidal source through cables which have negligible internal resistance and a total inductance of 2.28 mH. If the thyristors are triggered at an angle α = 45°, the commutation overlap angle in degree (rounded off to 2 decimal places) is_____.Correct answer is '4.80'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single-phase, full-bridge, fully controlled thyristor rectifier feeds a load comprising a 10 Ω resistance in series with a very large inductance. The rectifier is fed from an ideal 230 V, 50 Hz sinusoidal source through cables which have negligible internal resistance and a total inductance of 2.28 mH. If the thyristors are triggered at an angle α = 45°, the commutation overlap angle in degree (rounded off to 2 decimal places) is_____.Correct answer is '4.80'. Can you explain this answer?.
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