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For an infinitesimally small dipole in free space, the electric field Eθ in the far field is proportional to (e-jkr/r)sinθ, where k = 2π/λ. A vertical infinitesimally small electric dipole (δl < <λ is placed at a distance h(h > 0) above an infinite ideal conducting plane, as shown in the figure. The minimum value of h, for which one of the maxima in the far field radiation pattern occurs at 0 = 60°. isa)0.75λb)λc)0.25λd)0.5λCorrect answer is option 'B'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared
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Find important definitions, questions, meanings, examples, exercises and tests below for For an infinitesimally small dipole in free space, the electric field Eθ in the far field is proportional to (e-jkr/r)sinθ, where k = 2π/λ. A vertical infinitesimally small electric dipole (δl < <λ is placed at a distance h(h > 0) above an infinite ideal conducting plane, as shown in the figure. The minimum value of h, for which one of the maxima in the far field radiation pattern occurs at 0 = 60°. isa)0.75λb)λc)0.25λd)0.5λCorrect answer is option 'B'. Can you explain this answer?.
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Here you can find the meaning of For an infinitesimally small dipole in free space, the electric field Eθ in the far field is proportional to (e-jkr/r)sinθ, where k = 2π/λ. A vertical infinitesimally small electric dipole (δl < <λ is placed at a distance h(h > 0) above an infinite ideal conducting plane, as shown in the figure. The minimum value of h, for which one of the maxima in the far field radiation pattern occurs at 0 = 60°. isa)0.75λb)λc)0.25λd)0.5λCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
For an infinitesimally small dipole in free space, the electric field Eθ in the far field is proportional to (e-jkr/r)sinθ, where k = 2π/λ. A vertical infinitesimally small electric dipole (δl < <λ is placed at a distance h(h > 0) above an infinite ideal conducting plane, as shown in the figure. The minimum value of h, for which one of the maxima in the far field radiation pattern occurs at 0 = 60°. isa)0.75λb)λc)0.25λd)0.5λCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for For an infinitesimally small dipole in free space, the electric field Eθ in the far field is proportional to (e-jkr/r)sinθ, where k = 2π/λ. A vertical infinitesimally small electric dipole (δl < <λ is placed at a distance h(h > 0) above an infinite ideal conducting plane, as shown in the figure. The minimum value of h, for which one of the maxima in the far field radiation pattern occurs at 0 = 60°. isa)0.75λb)λc)0.25λd)0.5λCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of For an infinitesimally small dipole in free space, the electric field Eθ in the far field is proportional to (e-jkr/r)sinθ, where k = 2π/λ. A vertical infinitesimally small electric dipole (δl < <λ is placed at a distance h(h > 0) above an infinite ideal conducting plane, as shown in the figure. The minimum value of h, for which one of the maxima in the far field radiation pattern occurs at 0 = 60°. isa)0.75λb)λc)0.25λd)0.5λCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice For an infinitesimally small dipole in free space, the electric field Eθ in the far field is proportional to (e-jkr/r)sinθ, where k = 2π/λ. A vertical infinitesimally small electric dipole (δl < <λ is placed at a distance h(h > 0) above an infinite ideal conducting plane, as shown in the figure. The minimum value of h, for which one of the maxima in the far field radiation pattern occurs at 0 = 60°. isa)0.75λb)λc)0.25λd)0.5λCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice GATE tests.