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A small block is attached to a source supplying constant power to it. If it's displacement at t =4 sec is 16m on a horizontal smooth surface then it's displacement at t=9 sec will be: A. 36m b.48m c. 64m d.54m?
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A small block is attached to a source supplying constant power to it. ...
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A small block is attached to a source supplying constant power to it. ...
Displacement of the block at t=4 sec: 16m
Given that the block is attached to a source supplying constant power, we can infer that the work done on the block is constant. Since power is the rate at which work is done, a constant power implies a constant rate of work.
To find the displacement at t=9 sec, we need to calculate the work done on the block in the time interval from t=4 sec to t=9 sec.
Let's break down the solution into steps:
Step 1: Calculate the work done in the time interval from t=0 sec to t=4 sec.
Since the power is constant, we can use the formula:
Work = Power × Time
Given that the power is constant, we can substitute it with P (constant power) and the time interval from t=0 sec to t=4 sec.
Work (t=0 sec to t=4 sec) = P × (4 sec)
Step 2: Calculate the work done in the time interval from t=0 sec to t=9 sec.
Using the same formula as in Step 1, the work done in the time interval from t=0 sec to t=9 sec can be calculated as:
Work (t=0 sec to t=9 sec) = P × (9 sec)
Step 3: Calculate the difference in work between t=4 sec and t=9 sec.
To find the work done in the time interval from t=4 sec to t=9 sec, we subtract the work done in the time interval from t=0 sec to t=4 sec from the work done in the time interval from t=0 sec to t=9 sec.
Work (t=4 sec to t=9 sec) = Work (t=0 sec to t=9 sec) - Work (t=0 sec to t=4 sec)
Step 4: Calculate the displacement at t=9 sec.
The work done on the block is directly related to its displacement. Assuming no other external forces act on the block, we can use the equation:
Work = Force × Distance
Since the force acting on the block is constant, we can use the equation:
Work = Force × Displacement
Therefore, the displacement at t=9 sec can be calculated as:
Displacement (t=9 sec) = Work (t=4 sec to t=9 sec) / Force
Since the power is constant, the force acting on the block is also constant. Hence, we can substitute the formula for work done in Step 3 into the equation for displacement:
Displacement (t=9 sec) = [Work (t=0 sec to t=9 sec) - Work (t=0 sec to t=4 sec)] / Force
Finally, substitute the values into the equation to find the displacement at t=9 sec.
Given that the block is attached to a source supplying constant power, we can infer that the work done on the block is constant. Since power is the rate at which work is done, a constant power implies a constant rate of work.
To find the displacement at t=9 sec, we need to calculate the work done on the block in the time interval from t=4 sec to t=9 sec.
Let's break down the solution into steps:
Step 1: Calculate the work done in the time interval from t=0 sec to t=4 sec.
Since the power is constant, we can use the formula:
Work = Power × Time
Given that the power is constant, we can substitute it with P (constant power) and the time interval from t=0 sec to t=4 sec.
Work (t=0 sec to t=4 sec) = P × (4 sec)
Step 2: Calculate the work done in the time interval from t=0 sec to t=9 sec.
Using the same formula as in Step 1, the work done in the time interval from t=0 sec to t=9 sec can be calculated as:
Work (t=0 sec to t=9 sec) = P × (9 sec)
Step 3: Calculate the difference in work between t=4 sec and t=9 sec.
To find the work done in the time interval from t=4 sec to t=9 sec, we subtract the work done in the time interval from t=0 sec to t=4 sec from the work done in the time interval from t=0 sec to t=9 sec.
Work (t=4 sec to t=9 sec) = Work (t=0 sec to t=9 sec) - Work (t=0 sec to t=4 sec)
Step 4: Calculate the displacement at t=9 sec.
The work done on the block is directly related to its displacement. Assuming no other external forces act on the block, we can use the equation:
Work = Force × Distance
Since the force acting on the block is constant, we can use the equation:
Work = Force × Displacement
Therefore, the displacement at t=9 sec can be calculated as:
Displacement (t=9 sec) = Work (t=4 sec to t=9 sec) / Force
Since the power is constant, the force acting on the block is also constant. Hence, we can substitute the formula for work done in Step 3 into the equation for displacement:
Displacement (t=9 sec) = [Work (t=0 sec to t=9 sec) - Work (t=0 sec to t=4 sec)] / Force
Finally, substitute the values into the equation to find the displacement at t=9 sec.
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A small block is attached to a source supplying constant power to it. If it's displacement at t =4 sec is 16m on a horizontal smooth surface then it's displacement at t=9 sec will be: A. 36m b.48m c. 64m d.54m?
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A small block is attached to a source supplying constant power to it. If it's displacement at t =4 sec is 16m on a horizontal smooth surface then it's displacement at t=9 sec will be: A. 36m b.48m c. 64m d.54m? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A small block is attached to a source supplying constant power to it. If it's displacement at t =4 sec is 16m on a horizontal smooth surface then it's displacement at t=9 sec will be: A. 36m b.48m c. 64m d.54m? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A small block is attached to a source supplying constant power to it. If it's displacement at t =4 sec is 16m on a horizontal smooth surface then it's displacement at t=9 sec will be: A. 36m b.48m c. 64m d.54m?.
A small block is attached to a source supplying constant power to it. If it's displacement at t =4 sec is 16m on a horizontal smooth surface then it's displacement at t=9 sec will be: A. 36m b.48m c. 64m d.54m? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A small block is attached to a source supplying constant power to it. If it's displacement at t =4 sec is 16m on a horizontal smooth surface then it's displacement at t=9 sec will be: A. 36m b.48m c. 64m d.54m? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A small block is attached to a source supplying constant power to it. If it's displacement at t =4 sec is 16m on a horizontal smooth surface then it's displacement at t=9 sec will be: A. 36m b.48m c. 64m d.54m?.
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