Two small similar metal sphere A and B having charge 4 q and -4q when ...
Given:
- Two small similar metal sphere A and B having charge 4q and -4q
- When placed at a certain distance apart exert an electric force F on each other
- Another identical uncharged sphere C first touched with A then with B and then removed to infinity
To find: The force of interaction between A and B for the same separation
Solution:
Effect of Sphere C on A and B:
- Sphere C is uncharged, so it does not exert any electrostatic force on A or B
- When sphere C touches A, it will induce a charge on A due to the transfer of electrons
- This will create an opposite charge on sphere C
Charge on Sphere A:
- When sphere C touches A, it will induce a charge on A due to the transfer of electrons
- The charge on sphere A will be -4q (same as sphere C)
Charge on Sphere B:
- When sphere C touches B, it will induce a charge on B due to the transfer of electrons
- The charge on sphere B will be +4q (opposite to sphere C)
Force of Interaction between A and B:
- The force of interaction between A and B is given by Coulomb's Law: F = k * (q1 * q2) / r^2
- Here, k is the Coulomb's constant, q1 and q2 are the charges on the spheres, and r is the distance between them
- Since the charges on A and B are opposite, the force between them will be attractive
- The force between A and B after the interaction with C can be calculated as:
- F' = k * (4q * (-4q)) / r^2 = -16kq^2 / r^2
- This is one-fourth of the original force F, since the charges on A and B were originally 4q and -4q respectively
- Therefore, the answer is (b) F/8
Two small similar metal sphere A and B having charge 4 q and -4q when ...
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