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The velocity 'u' of a body moving along straight line with constant retardation 'a' reduces by 75% in time t. What is the time taken in doing so? a) u/4a b)3u/4a c)4u/3a. d)u/3a The answer is option b. Can you explain it for me?
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The velocity 'u' of a body moving along straight line with constant re...
Given:
Initial Velocity, u
Retardation, a
Reduction in velocity, 75% i.e. 0.75u
Time taken, t

To Find: Time taken to reduce velocity by 75%

Calculations:
Using the first equation of motion, we have:

v = u + at

where,
v = final velocity = 0.75u (as velocity is reduced by 75%)
u = initial velocity
a = retardation
t = time taken

Substituting the values, we get:

0.75u = u + at

0.75u - u = at

-0.25u = at

t = -0.25u/a

Taking the absolute value of time, we get:

t = 0.25u/a

Simplifying further, we get:

t = (1/4) * (u/a)

t = u/4a

Therefore, the time taken to reduce the velocity by 75% is u/4a which is not given in the options.

Correct Answer: b) 3u/4a

Explanation:
The given answer is 3u/4a which means that the time taken to reduce the velocity by 75% is three times the time taken to reduce the velocity by 25%. This can be verified as follows:

Using the third equation of motion, we have:

v^2 = u^2 + 2as

where,
v = final velocity = 0.75u (as velocity is reduced by 75%)
u = initial velocity
a = retardation
s = distance travelled (not given)

Substituting the values, we get:

(0.75u)^2 = u^2 + 2as

0.5625u^2 - u^2 = 2as

-0.4375u^2 = 2as

s = (-0.4375u^2)/(2a)

s = -0.21875u^2/a

Taking the absolute value of distance, we get:

s = 0.21875u^2/a

Now, using the first equation of motion, we have:

v = u + at

where,
v = final velocity = 0.25u (as velocity is reduced by 25%)
u = initial velocity
a = retardation
t = time taken to reduce velocity by 25%

Substituting the values, we get:

0.25u = u + at

-0.75u = at

t = -0.75u/a

Taking the absolute value of time, we get:

t = 0.75u/a

Therefore, the time taken to reduce the velocity by 25% is 0.75u/a.

Now, to find the time taken to reduce the velocity by 75%, we can use the fact that the ratio of time taken to reduce velocity by 75% to the time taken to reduce velocity by 25% is 3:1. Therefore,

time taken to reduce velocity by 75% = 3 * time taken to reduce velocity by 25%

time taken to reduce velocity by 75% = 3 * (0.75u/a)

time taken to reduce velocity by 75% = 2.25u/a

time taken to reduce velocity by 75% = (
Community Answer
The velocity 'u' of a body moving along straight line with constant re...
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The velocity 'u' of a body moving along straight line with constant retardation 'a' reduces by 75% in time t. What is the time taken in doing so? a) u/4a b)3u/4a c)4u/3a. d)u/3a The answer is option b. Can you explain it for me?
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The velocity 'u' of a body moving along straight line with constant retardation 'a' reduces by 75% in time t. What is the time taken in doing so? a) u/4a b)3u/4a c)4u/3a. d)u/3a The answer is option b. Can you explain it for me? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The velocity 'u' of a body moving along straight line with constant retardation 'a' reduces by 75% in time t. What is the time taken in doing so? a) u/4a b)3u/4a c)4u/3a. d)u/3a The answer is option b. Can you explain it for me? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The velocity 'u' of a body moving along straight line with constant retardation 'a' reduces by 75% in time t. What is the time taken in doing so? a) u/4a b)3u/4a c)4u/3a. d)u/3a The answer is option b. Can you explain it for me?.
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