Problem:

In School There Are Some Bicycles And 4 Wheeler Wagons. One Tuesday There Are 190 Wheels In The Campus. How Many Bicycles Are There?

Solution:

Let's assume that the number of bicycles in the campus is x and the number of 4 wheeler wagons is y.

We know that:

- A bicycle has two wheels
- A 4 wheeler wagon has four wheels

So, the total number of wheels in the campus can be represented by the following equation:

2x + 4y = 190

Simplifying the equation:

2x + 4y = 190
Divide both sides by 2
x + 2y = 95

Now we have two unknowns x and y, but we have only one equation. We need another equation to solve for both x and y.

Let's use the fact that we are dealing with whole numbers. This means that both x and y must be positive integers.

Method 1: Brute Force Method

We can use a brute force method to find the solution. We can start with x = 1 and y = 1 and keep increasing the values of x and y until we find a solution that satisfies both equations.

x = 1, y = 1
x + 2y = 95
1 + 2(1) = 3 (not equal to 95)

x = 1, y = 2
x + 2y = 95
1 + 2(2) = 5 (not equal to 95)

x = 1, y = 3
x + 2y = 95
1 + 2(3) = 7 (not equal to 95)

x = 1, y = 4
x + 2y = 95
1 + 2(4) = 9 (not equal to 95)

x = 1, y = 5
x + 2y = 95
1 + 2(5) = 11 (not equal to 95)

x = 1, y = 6
x + 2y = 95
1 + 2(6) = 13 (not equal to 95)

x = 1, y = 7
x + 2y = 95
1 + 2(7) = 15 (not equal to 95)

x = 1, y = 8
x + 2y = 95
1 + 2(8) = 17 (not equal to 95)

x = 1, y = 9
x + 2y = 95
1 + 2(9) = 19 (not equal to 95)

x = 1, y = 10
x + 2y = 95
1 + 2(10) = 21 (not equal to 95)

x = 1, y = 11
x + 2y = 95
1 + 2(11) = 23 (not equal to 95)

x = 1, y = 12
x + 2y = 95
1 + 2(12) = 25 (not equal to 95)

x =