You need to configure a server that is on the subnet 192.168.19.24/29. The router has the first available host address. Which of the following should you assign to the server?a)192.168.19.0 255.255.255.0b)192.168.19.33 255.255.255.240c)192.168.19.26 255.255.255.248d)192.168.19.31 255.255.255.248Correct answer is option 'C'. Can you explain this answer?

Question

Answer

Question Analysis
- The subnet for the server is given as 192.168.19.24/29.
- The router has the first available host address.

Understanding Subnetting
- Subnetting is the process of dividing a network into smaller subnetworks.
- It allows for efficient utilization of IP addresses and improves network management.

Subnet Calculation
- The subnet 192.168.19.24/29 indicates that the first 29 bits are network bits and the remaining 3 bits are host bits.
- The subnet mask for /29 is 255.255.255.248.
- This means that there are 8 possible IP addresses in the subnet, with 6 usable addresses for hosts.

Identification of Available Host Addresses
- In a /29 subnet, the first IP address is the network address, and the last IP address is the broadcast address.
- The remaining 6 addresses are available for hosts.
- Since the router has the first available host address, it would be assigned the IP address 192.168.19.25.

Assignment of IP Address to Server
- The server is assigned an IP address from the available host addresses.
- The options provided are:
a) 192.168.19.0
b) 192.168.19.33
c) 192.168.19.26
d) 192.168.19.31

Analysis of Options
a) 192.168.19.0 is the network address and cannot be assigned to a host.
b) 192.168.19.33 is outside the range of available host addresses in the /29 subnet.
c) 192.168.19.26 is within the range of available host addresses in the /29 subnet and can be assigned to the server.
d) 192.168.19.31 is the broadcast address and cannot be assigned to a host.

Conclusion
- Based on the analysis, the correct option to assign to the server is c) 192.168.19.26 255.255.255.248.

Similar Quant Doubts

Using the illustration from the previous question, what would be the IP address of S0 if you were using the first subnet? The network ID is 192.168.10.0/28 and you need to use the last available IP address in the range. Again, the zero subnet should not be considered valid for this question.

Using the following illustration, what would be the IP address of E0 if you were using the eighth subnet? The network ID is 192.168.10.0/28 and you need to use the last available IP address in the range. The zero subnet should not be considered valid for this question.

You have a network that needs 29 subnets while maximizing the number of host addresses available on each subnet. How many bits must you borrow from the host field to provide the correct subnet mask?

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