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You have an interface on a router with the IP address of 192.168.192.10/29. What is the broadcast address the hosts will use on this LAN?
- a)192.168.192.15
- b)192.168.192.31
- c)192.168.192.63
- d)192.168.192.127
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
You have an interface on a router with the IP address of 192.168.192.1...
A /29 (255.255.255.248) has a block size of 8 in the fourth octet. This means the subnets are 0, 8, 16, 24, etc. 10 is in the 8 subnet. The next subnet is 16, so 15 is the broadcast address.
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You have an interface on a router with the IP address of 192.168.192.1...
Answer:
Subnetting is the process of dividing a network into smaller sub-networks based on IP addressing. When we subnet a network, we need to find out the subnet ID, subnet mask, broadcast address, and range of usable IP addresses.
Given that the IP address of the router interface is 192.168.192.10/29, we need to find out the broadcast address for the hosts on this LAN.
Step-by-step solution:
1. Convert the subnet mask to binary. The subnet mask for /29 is 255.255.255.248, which is 11111111.11111111.11111111.11111000 in binary.
2. Determine the subnet ID. To find the subnet ID, we perform a bitwise AND operation between the IP address and the subnet mask.
192.168.192.10 = 11000000.10101000.11000000.00001010
255.255.255.248 = 11111111.11111111.11111111.11111000
Subnet ID = 11000000.10101000.11000000.00001000 (192.168.192.8)
3. Determine the broadcast address. To find the broadcast address, we perform a bitwise OR operation between the subnet ID and the binary complement of the subnet mask.
Binary complement of 248 = 00000111
Subnet ID = 11000000.10101000.11000000.00001000
Binary complement of subnet mask = 00000111.11111111.11111111.11111000
Performing bitwise OR operation = 11000000.10101000.11000000.00001111 (192.168.192.15)
Therefore, the broadcast address that the hosts will use on this LAN is 192.168.192.15, which is option A.
Subnetting is the process of dividing a network into smaller sub-networks based on IP addressing. When we subnet a network, we need to find out the subnet ID, subnet mask, broadcast address, and range of usable IP addresses.
Given that the IP address of the router interface is 192.168.192.10/29, we need to find out the broadcast address for the hosts on this LAN.
Step-by-step solution:
1. Convert the subnet mask to binary. The subnet mask for /29 is 255.255.255.248, which is 11111111.11111111.11111111.11111000 in binary.
2. Determine the subnet ID. To find the subnet ID, we perform a bitwise AND operation between the IP address and the subnet mask.
192.168.192.10 = 11000000.10101000.11000000.00001010
255.255.255.248 = 11111111.11111111.11111111.11111000
Subnet ID = 11000000.10101000.11000000.00001000 (192.168.192.8)
3. Determine the broadcast address. To find the broadcast address, we perform a bitwise OR operation between the subnet ID and the binary complement of the subnet mask.
Binary complement of 248 = 00000111
Subnet ID = 11000000.10101000.11000000.00001000
Binary complement of subnet mask = 00000111.11111111.11111111.11111000
Performing bitwise OR operation = 11000000.10101000.11000000.00001111 (192.168.192.15)
Therefore, the broadcast address that the hosts will use on this LAN is 192.168.192.15, which is option A.
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You have an interface on a router with the IP address of 192.168.192.10/29. What is the broadcast address the hosts will use on this LAN?a)192.168.192.15b)192.168.192.31c)192.168.192.63d)192.168.192.127Correct answer is option 'A'. Can you explain this answer?
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