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You have an interface on a router with the IP address of 192.168.192.10/29. Including the router interface, how many hosts can have IP addresses on the LAN attached to the router interface?
- a)6
- b)8
- c)30
- d)32
Correct answer is option 'A'. Can you explain this answer?
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You have an interface on a router with the IP address of 192.168.192.1...
A /29 (255.255.255.248), regardless of the class of address, has only 3 host bits. Six hosts is the maximum number of hosts on this LAN, including the router interface.
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You have an interface on a router with the IP address of 192.168.192.1...
Given information:
- IP address of router interface: 192.168.192.10/29
To find:
- Number of hosts that can have IP addresses on the LAN attached to the router interface
Solution:
- The IP address notation 192.168.192.10/29 means that the IP address is 192.168.192.10 and the subnet mask is 255.255.255.248.
- The subnet mask determines the number of bits used for the network portion of the address and the number of bits used for the host portion of the address.
- In this case, the subnet mask has 29 bits set to 1, leaving only 3 bits for the host portion of the address.
- This means that there are 2^3 or 8 possible host addresses on this network.
- However, one of these addresses is reserved for the network address (192.168.192.8 in this case) and another is reserved for the broadcast address (192.168.192.15 in this case).
- Therefore, the number of usable host addresses is 8 - 2 = 6.
Answer:
- Therefore, the correct answer is option A, 6 hosts can have IP addresses on the LAN attached to the router interface.
- IP address of router interface: 192.168.192.10/29
To find:
- Number of hosts that can have IP addresses on the LAN attached to the router interface
Solution:
- The IP address notation 192.168.192.10/29 means that the IP address is 192.168.192.10 and the subnet mask is 255.255.255.248.
- The subnet mask determines the number of bits used for the network portion of the address and the number of bits used for the host portion of the address.
- In this case, the subnet mask has 29 bits set to 1, leaving only 3 bits for the host portion of the address.
- This means that there are 2^3 or 8 possible host addresses on this network.
- However, one of these addresses is reserved for the network address (192.168.192.8 in this case) and another is reserved for the broadcast address (192.168.192.15 in this case).
- Therefore, the number of usable host addresses is 8 - 2 = 6.
Answer:
- Therefore, the correct answer is option A, 6 hosts can have IP addresses on the LAN attached to the router interface.
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