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Steam is passed into 22 gm of water at 20 degree C . The mass of water that will be present when the water acquires a temperature of 90 degree C ( latent heat of steam is 540 cal/ g) is a). 24.83gm b)24 gm c) 36.6gm d)30gm?
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Steam is passed into 22 gm of water at 20 degree C . The mass of water...
Solution:
Given, Mass of water = 22 gm
Initial temperature of water = 20°C
Final temperature of water = 90°C
Latent heat of steam = 540 cal/gm
To solve this problem, we need to apply the principle of calorimetry which states that the heat gained by one body is equal to the heat lost by the other body.
Let's assume that the mass of steam required to raise the temperature of water from 20°C to 90°C is m gm.
Heat gained by steam = Heat lost by water
m * 540 cal/gm = 22 gm * specific heat of water * (90°C - 20°C)
We know that the specific heat of water is 1 cal/gm°C.
m * 540 = 22 * 1 * 70
m = (22 * 70)/540 = 2.85 gm
Therefore, the mass of water present after steam condenses at 90°C is:
Mass of water = Initial mass of water + Mass of steam condensed
Mass of water = 22 gm + 2.85 gm = 24.85 gm
Hence, the answer is option (a) 24.83 gm.
HTML code for the solution:
Given, Mass of water = 22 gm
Initial temperature of water = 20°C
Final temperature of water = 90°C
Latent heat of steam = 540 cal/gm
To solve this problem, we need to apply the principle of calorimetry which states that the heat gained by one body is equal to the heat lost by the other body.
Let's assume that the mass of steam required to raise the temperature of water from 20°C to 90°C is m gm.
Heat gained by steam = Heat lost by water
m * 540 cal/gm = 22 gm * specific heat of water * (90°C - 20°C)
We know that the specific heat of water is 1 cal/gm°C.
m * 540 = 22 * 1 * 70
m = (22 * 70)/540 = 2.85 gm
Therefore, the mass of water present after steam condenses at 90°C is:
Mass of water = Initial mass of water + Mass of steam condensed
Mass of water = 22 gm + 2.85 gm = 24.85 gm
Hence, the answer is option (a) 24.83 gm.
HTML code for the solution:
Solution:
Given,
Mass of water = 22 gm
Initial temperature of water = 20°C
Final temperature of water = 90°C
Latent heat of steam = 540 cal/gm
Mass of water = 22 gm
Initial temperature of water = 20°C
Final temperature of water = 90°C
Latent heat of steam = 540 cal/gm
To solve this problem, we need to apply the principle of calorimetry which states that the heat gained by one body is equal to the heat lost by the other body.
Let's assume that the mass of steam required to raise the temperature of water from 20°C to 90°C is m gm.
Heat gained by steam = Heat lost by water
m * 540 cal/gm = 22 gm * specific heat of water * (90°C - 20°C)
We know that the specific heat of water is 1 cal/gm°C.
m * 540 = 22 * 1 * 70
m = (22 * 70)/540 = 2.85 gm
m * 540 cal/gm = 22 gm * specific heat of water * (90°C - 20°C)
We know that the specific heat of water is 1 cal/gm°C.
m * 540 = 22 * 1 * 70
m = (22 * 70)/540 = 2.85 gm
Therefore, the mass of water present after steam condenses at 90°C is:
Mass of water = Initial mass of water + Mass of steam condensed
Mass of water = 22 gm + 2.85 gm = 24.85 gm
Mass of water = Initial mass of water + Mass of steam condensed
Mass of water = 22 gm + 2.85 gm = 24.85 gm
Hence, the answer is option (a) 24.83 gm.
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Steam is passed into 22 gm of water at 20 degree C . The mass of water...
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Steam is passed into 22 gm of water at 20 degree C . The mass of water that will be present when the water acquires a temperature of 90 degree C ( latent heat of steam is 540 cal/ g) is a). 24.83gm b)24 gm c) 36.6gm d)30gm?
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Steam is passed into 22 gm of water at 20 degree C . The mass of water that will be present when the water acquires a temperature of 90 degree C ( latent heat of steam is 540 cal/ g) is a). 24.83gm b)24 gm c) 36.6gm d)30gm? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Steam is passed into 22 gm of water at 20 degree C . The mass of water that will be present when the water acquires a temperature of 90 degree C ( latent heat of steam is 540 cal/ g) is a). 24.83gm b)24 gm c) 36.6gm d)30gm? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Steam is passed into 22 gm of water at 20 degree C . The mass of water that will be present when the water acquires a temperature of 90 degree C ( latent heat of steam is 540 cal/ g) is a). 24.83gm b)24 gm c) 36.6gm d)30gm?.
Steam is passed into 22 gm of water at 20 degree C . The mass of water that will be present when the water acquires a temperature of 90 degree C ( latent heat of steam is 540 cal/ g) is a). 24.83gm b)24 gm c) 36.6gm d)30gm? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Steam is passed into 22 gm of water at 20 degree C . The mass of water that will be present when the water acquires a temperature of 90 degree C ( latent heat of steam is 540 cal/ g) is a). 24.83gm b)24 gm c) 36.6gm d)30gm? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Steam is passed into 22 gm of water at 20 degree C . The mass of water that will be present when the water acquires a temperature of 90 degree C ( latent heat of steam is 540 cal/ g) is a). 24.83gm b)24 gm c) 36.6gm d)30gm?.
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