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2Kg ice at –10°C , 1 Kg of ice at 0°C and 8.5 Kg of water at 20°C are mixed together. Then final amount of ice remaining is - [Given specific heat of ice = 0.5 cal/g°C, Specific heat of water = 1 cal/g°C, Latent heat of fusion of ice = 80 cal/g]a)2 Kgb)2.5 Kgc)1.5 Kgd)1 KgCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 2Kg ice at –10°C , 1 Kg of ice at 0°C and 8.5 Kg of water at 20°C are mixed together. Then final amount of ice remaining is - [Given specific heat of ice = 0.5 cal/g°C, Specific heat of water = 1 cal/g°C, Latent heat of fusion of ice = 80 cal/g]a)2 Kgb)2.5 Kgc)1.5 Kgd)1 KgCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2Kg ice at –10°C , 1 Kg of ice at 0°C and 8.5 Kg of water at 20°C are mixed together. Then final amount of ice remaining is - [Given specific heat of ice = 0.5 cal/g°C, Specific heat of water = 1 cal/g°C, Latent heat of fusion of ice = 80 cal/g]a)2 Kgb)2.5 Kgc)1.5 Kgd)1 KgCorrect answer is option 'D'. Can you explain this answer?.

Solutions for 2Kg ice at –10°C , 1 Kg of ice at 0°C and 8.5 Kg of water at 20°C are mixed together. Then final amount of ice remaining is - [Given specific heat of ice = 0.5 cal/g°C, Specific heat of water = 1 cal/g°C, Latent heat of fusion of ice = 80 cal/g]a)2 Kgb)2.5 Kgc)1.5 Kgd)1 KgCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of 2Kg ice at –10°C , 1 Kg of ice at 0°C and 8.5 Kg of water at 20°C are mixed together. Then final amount of ice remaining is - [Given specific heat of ice = 0.5 cal/g°C, Specific heat of water = 1 cal/g°C, Latent heat of fusion of ice = 80 cal/g]a)2 Kgb)2.5 Kgc)1.5 Kgd)1 KgCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of 2Kg ice at –10°C , 1 Kg of ice at 0°C and 8.5 Kg of water at 20°C are mixed together. Then final amount of ice remaining is - [Given specific heat of ice = 0.5 cal/g°C, Specific heat of water = 1 cal/g°C, Latent heat of fusion of ice = 80 cal/g]a)2 Kgb)2.5 Kgc)1.5 Kgd)1 KgCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for 2Kg ice at –10°C , 1 Kg of ice at 0°C and 8.5 Kg of water at 20°C are mixed together. Then final amount of ice remaining is - [Given specific heat of ice = 0.5 cal/g°C, Specific heat of water = 1 cal/g°C, Latent heat of fusion of ice = 80 cal/g]a)2 Kgb)2.5 Kgc)1.5 Kgd)1 KgCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of 2Kg ice at –10°C , 1 Kg of ice at 0°C and 8.5 Kg of water at 20°C are mixed together. Then final amount of ice remaining is - [Given specific heat of ice = 0.5 cal/g°C, Specific heat of water = 1 cal/g°C, Latent heat of fusion of ice = 80 cal/g]a)2 Kgb)2.5 Kgc)1.5 Kgd)1 KgCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice 2Kg ice at –10°C , 1 Kg of ice at 0°C and 8.5 Kg of water at 20°C are mixed together. Then final amount of ice remaining is - [Given specific heat of ice = 0.5 cal/g°C, Specific heat of water = 1 cal/g°C, Latent heat of fusion of ice = 80 cal/g]a)2 Kgb)2.5 Kgc)1.5 Kgd)1 KgCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice NEET tests.