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A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is?
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A disk brake has two friction lining with the outside lining and insid...
Torque is a measure of the force that causes an object to rotate around an axis. In this case, the torque applied by the brake on the rotating part can be determined using the following steps:
1. Convert the given axial force from kilonewtons (KN) to newtons (N).
- 10 KN = 10,000 N
2. Convert the rotational speed from revolutions per minute (RPM) to radians per second (rad/s).
- 1 RPM = (2π/60) rad/s
- 8000 RPM = (2π/60) * 8000 = 837.76 rad/s
3. Calculate the effective radius at which the frictional force acts.
- The effective radius can be determined by taking the average of the outside and inside lining diameters.
- Effective radius = (120 mm + 60 mm) / 2 = 90 mm = 0.09 m
4. Calculate the frictional force acting on the rotating part.
- The frictional force can be determined using the equation: Frictional force = coefficient of friction * normal force
- Normal force can be calculated using the equation: Normal force = axial force / number of lining surfaces
- In this case, there are two lining surfaces (inside and outside).
- Normal force = 10,000 N / 2 = 5,000 N
- Frictional force = 0.35 * 5,000 N = 1,750 N
5. Calculate the torque applied by the brake on the rotating part.
- The torque can be determined using the equation: Torque = frictional force * effective radius
- Torque = 1,750 N * 0.09 m = 157.5 N-m
Therefore, the torque applied by the brake on the rotating part is 157.5 N-m.
1. Convert the given axial force from kilonewtons (KN) to newtons (N).
- 10 KN = 10,000 N
2. Convert the rotational speed from revolutions per minute (RPM) to radians per second (rad/s).
- 1 RPM = (2π/60) rad/s
- 8000 RPM = (2π/60) * 8000 = 837.76 rad/s
3. Calculate the effective radius at which the frictional force acts.
- The effective radius can be determined by taking the average of the outside and inside lining diameters.
- Effective radius = (120 mm + 60 mm) / 2 = 90 mm = 0.09 m
4. Calculate the frictional force acting on the rotating part.
- The frictional force can be determined using the equation: Frictional force = coefficient of friction * normal force
- Normal force can be calculated using the equation: Normal force = axial force / number of lining surfaces
- In this case, there are two lining surfaces (inside and outside).
- Normal force = 10,000 N / 2 = 5,000 N
- Frictional force = 0.35 * 5,000 N = 1,750 N
5. Calculate the torque applied by the brake on the rotating part.
- The torque can be determined using the equation: Torque = frictional force * effective radius
- Torque = 1,750 N * 0.09 m = 157.5 N-m
Therefore, the torque applied by the brake on the rotating part is 157.5 N-m.
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A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is?
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A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is?.
A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is?.
Solutions for A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is? in English & in Hindi are available as part of our courses for GATE.
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Here you can find the meaning of A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is? defined & explained in the simplest way possible. Besides giving the explanation of
A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is?, a detailed solution for A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is? has been provided alongside types of A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is? theory, EduRev gives you an
ample number of questions to practice A disk brake has two friction lining with the outside lining and inside lining diameters as 120mm and 60 mm, respectively. The coefficient of friction at the interface of lining and rotating part is 0.35. A 10 KN axial force is applied to stop the part Rotating at 8000 rpm. Assume uniform wear rate of disk lining and heat transfer by convection only. The torque (in N-m) Applied by the brake on the rotatii part is? tests, examples and also practice GATE tests.
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