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What would be the osmotic pressure of a solution containing 5.85g NaCl and 3.42g sugar in 500 mL at 27⁰C? A. 103.4atm B. 10.34atm C . 1.034atm D. 0.1034atm Ans is B.plz explain this?
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What would be the osmotic pressure of a solution containing 5.85g NaCl...
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What would be the osmotic pressure of a solution containing 5.85g NaCl...
Calculation of osmotic pressure of the given solution involves the following steps:
Determining the number of particles in solution:
- NaCl dissociates into two ions (Na+ and Cl-) in the solution.
- Sugar does not dissociate in solution.
- Therefore, total number of particles (i) in solution = 2 + 1 = 3
Calculating the molarity of the solution:
- Molarity (M) = moles of solute / volume of solution in liters
- Moles of NaCl = 5.85 g / 58.44 g/mol = 0.1 mol
- Moles of sugar = 3.42 g / 342.3 g/mol = 0.01 mol
- Total moles of solute = 0.1 + 0.01 = 0.11 mol
- Volume of solution = 500 mL = 0.5 L
- Molarity of solution = 0.11 mol / 0.5 L = 0.22 M
Calculating the van't Hoff factor (i) of the solute:
- NaCl dissociates into two ions, so i = 2
- Sugar does not dissociate, so i = 1
Calculating the osmotic pressure (π) of the solution:
- π = iMRT, where R is the gas constant (0.0821 L atm mol^-1 K^-1) and T is the temperature in Kelvin (27°C = 300 K)
- For NaCl: π = 2 x 0.22 x 0.0821 x 300 = 10.34 atm
- For sugar: π = 1 x 0.22 x 0.0821 x 300 = 1.81 atm
- Total osmotic pressure = 10.34 + 1.81 = 12.15 atm
Therefore, the osmotic pressure of the given solution containing 5.85g NaCl and 3.42g sugar in 500 mL at 27⁰C is 10.34 atm (Option B).
Determining the number of particles in solution:
- NaCl dissociates into two ions (Na+ and Cl-) in the solution.
- Sugar does not dissociate in solution.
- Therefore, total number of particles (i) in solution = 2 + 1 = 3
Calculating the molarity of the solution:
- Molarity (M) = moles of solute / volume of solution in liters
- Moles of NaCl = 5.85 g / 58.44 g/mol = 0.1 mol
- Moles of sugar = 3.42 g / 342.3 g/mol = 0.01 mol
- Total moles of solute = 0.1 + 0.01 = 0.11 mol
- Volume of solution = 500 mL = 0.5 L
- Molarity of solution = 0.11 mol / 0.5 L = 0.22 M
Calculating the van't Hoff factor (i) of the solute:
- NaCl dissociates into two ions, so i = 2
- Sugar does not dissociate, so i = 1
Calculating the osmotic pressure (π) of the solution:
- π = iMRT, where R is the gas constant (0.0821 L atm mol^-1 K^-1) and T is the temperature in Kelvin (27°C = 300 K)
- For NaCl: π = 2 x 0.22 x 0.0821 x 300 = 10.34 atm
- For sugar: π = 1 x 0.22 x 0.0821 x 300 = 1.81 atm
- Total osmotic pressure = 10.34 + 1.81 = 12.15 atm
Therefore, the osmotic pressure of the given solution containing 5.85g NaCl and 3.42g sugar in 500 mL at 27⁰C is 10.34 atm (Option B).
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What would be the osmotic pressure of a solution containing 5.85g NaCl and 3.42g sugar in 500 mL at 27⁰C? A. 103.4atm B. 10.34atm C . 1.034atm D. 0.1034atm Ans is B.plz explain this?
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What would be the osmotic pressure of a solution containing 5.85g NaCl and 3.42g sugar in 500 mL at 27⁰C? A. 103.4atm B. 10.34atm C . 1.034atm D. 0.1034atm Ans is B.plz explain this? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What would be the osmotic pressure of a solution containing 5.85g NaCl and 3.42g sugar in 500 mL at 27⁰C? A. 103.4atm B. 10.34atm C . 1.034atm D. 0.1034atm Ans is B.plz explain this? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What would be the osmotic pressure of a solution containing 5.85g NaCl and 3.42g sugar in 500 mL at 27⁰C? A. 103.4atm B. 10.34atm C . 1.034atm D. 0.1034atm Ans is B.plz explain this?.
What would be the osmotic pressure of a solution containing 5.85g NaCl and 3.42g sugar in 500 mL at 27⁰C? A. 103.4atm B. 10.34atm C . 1.034atm D. 0.1034atm Ans is B.plz explain this? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about What would be the osmotic pressure of a solution containing 5.85g NaCl and 3.42g sugar in 500 mL at 27⁰C? A. 103.4atm B. 10.34atm C . 1.034atm D. 0.1034atm Ans is B.plz explain this? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What would be the osmotic pressure of a solution containing 5.85g NaCl and 3.42g sugar in 500 mL at 27⁰C? A. 103.4atm B. 10.34atm C . 1.034atm D. 0.1034atm Ans is B.plz explain this?.
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