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The P.E. function of a particle executing linear simple harmonic motion is given by V (x) = 1/2 kx2, where k, force constant of oscillator is equal to 0.5 N/m. The amplitude of particle when its total energy is 1 J is equal toa)2 √2 mb)2 mc)√2 md)None of theseCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The P.E. function of a particle executing linear simple harmonic motion is given by V (x) = 1/2 kx2, where k, force constant of oscillator is equal to 0.5 N/m. The amplitude of particle when its total energy is 1 J is equal toa)2 √2 mb)2 mc)√2 md)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The P.E. function of a particle executing linear simple harmonic motion is given by V (x) = 1/2 kx2, where k, force constant of oscillator is equal to 0.5 N/m. The amplitude of particle when its total energy is 1 J is equal toa)2 √2 mb)2 mc)√2 md)None of theseCorrect answer is option 'B'. Can you explain this answer?.

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