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An object 2.0cm in size is placed 20.0cm in front of a concave mirror of focal length 10.0cm .Find the distance from the mirror at which a screen should be placed in order to obtain sharp image.What will be the size and nature of the image formed ?
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An object 2.0cm in size is placed 20.0cm in front of a concave mirror ...
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An object 2.0cm in size is placed 20.0cm in front of a concave mirror ...
Given:
Size of the object, h = 2.0 cm
Distance of the object from the mirror, u = -20.0 cm (negative sign indicates that the object is placed in front of the mirror)
Focal length of the mirror, f = -10.0 cm (negative sign indicates that the mirror is concave)
To find:
Distance of the screen from the mirror, v
Size and nature of the image formed
Solution:
We can use the mirror formula to find the distance of the screen from the mirror.
Mirror formula is given by:
1/f = 1/u + 1/v
Substituting the given values,
1/-10 = 1/-20 + 1/v
Solving for v, we get
v = -20 cm
So, the screen should be placed 20 cm away from the mirror.
Size of the image:
We can use the magnification formula to find the size of the image.
Magnification formula is given by:
m = -v/u
Substituting the given values,
m = -(-20)/(-20) = 1
So, the magnification is 1.
Size of the image = Magnification x Size of the object
Size of the image = 1 x 2.0 cm = 2.0 cm
Therefore, the size of the image formed is 2.0 cm.
Nature of the image:
Since the magnification is positive, the image formed is erect.
Since the object is placed between the pole and the focus of the mirror, the image formed is virtual.
Therefore, the nature of the image formed is virtual and erect.
Conclusion:
The distance of the screen from the mirror is 20.0 cm. The size of the image formed is 2.0 cm and the nature of the image formed is virtual and erect.
Size of the object, h = 2.0 cm
Distance of the object from the mirror, u = -20.0 cm (negative sign indicates that the object is placed in front of the mirror)
Focal length of the mirror, f = -10.0 cm (negative sign indicates that the mirror is concave)
To find:
Distance of the screen from the mirror, v
Size and nature of the image formed
Solution:
We can use the mirror formula to find the distance of the screen from the mirror.
Mirror formula is given by:
1/f = 1/u + 1/v
Substituting the given values,
1/-10 = 1/-20 + 1/v
Solving for v, we get
v = -20 cm
So, the screen should be placed 20 cm away from the mirror.
Size of the image:
We can use the magnification formula to find the size of the image.
Magnification formula is given by:
m = -v/u
Substituting the given values,
m = -(-20)/(-20) = 1
So, the magnification is 1.
Size of the image = Magnification x Size of the object
Size of the image = 1 x 2.0 cm = 2.0 cm
Therefore, the size of the image formed is 2.0 cm.
Nature of the image:
Since the magnification is positive, the image formed is erect.
Since the object is placed between the pole and the focus of the mirror, the image formed is virtual.
Therefore, the nature of the image formed is virtual and erect.
Conclusion:
The distance of the screen from the mirror is 20.0 cm. The size of the image formed is 2.0 cm and the nature of the image formed is virtual and erect.
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An object 2.0cm in size is placed 20.0cm in front of a concave mirror of focal length 10.0cm .Find the distance from the mirror at which a screen should be placed in order to obtain sharp image.What will be the size and nature of the image formed ?
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An object 2.0cm in size is placed 20.0cm in front of a concave mirror of focal length 10.0cm .Find the distance from the mirror at which a screen should be placed in order to obtain sharp image.What will be the size and nature of the image formed ? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An object 2.0cm in size is placed 20.0cm in front of a concave mirror of focal length 10.0cm .Find the distance from the mirror at which a screen should be placed in order to obtain sharp image.What will be the size and nature of the image formed ? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object 2.0cm in size is placed 20.0cm in front of a concave mirror of focal length 10.0cm .Find the distance from the mirror at which a screen should be placed in order to obtain sharp image.What will be the size and nature of the image formed ?.
An object 2.0cm in size is placed 20.0cm in front of a concave mirror of focal length 10.0cm .Find the distance from the mirror at which a screen should be placed in order to obtain sharp image.What will be the size and nature of the image formed ? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about An object 2.0cm in size is placed 20.0cm in front of a concave mirror of focal length 10.0cm .Find the distance from the mirror at which a screen should be placed in order to obtain sharp image.What will be the size and nature of the image formed ? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object 2.0cm in size is placed 20.0cm in front of a concave mirror of focal length 10.0cm .Find the distance from the mirror at which a screen should be placed in order to obtain sharp image.What will be the size and nature of the image formed ?.
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