An object 4 cm in size placed at 25 cm in front of a concave mirror of...
1/f=1/u+1/vu=-25cm1/-15=1/-25+1/(+v)===>1/v=-1/15+1/251/v=-25+15/15*251/v=-2/75v=-75/2m=-(v/u)=-(75/2/-25/1)=-3/2=-1.5m=-1.5so Image is magnified and real ,inverted
An object 4 cm in size placed at 25 cm in front of a concave mirror of...
Calculation of Image Distance
Given:
Object distance (u) = -25 cm (because the object is placed in front of the mirror)
Focal length (f) = -15 cm (because the mirror is concave)
Using the formula: 1/f = 1/u + 1/v
Where v is the image distance
Substituting the values, we get:
1/-15 = 1/-25 + 1/v
Solving for v, we get:
v = -37.5 cm
The negative sign indicates that the image is formed behind the mirror, which is expected for a concave mirror.
Calculation of Image Size
Using the formula: magnification = -v/u
Substituting the values, we get:
magnification = -(-37.5)/(-25) = 1.5
The negative sign indicates that the image is inverted.
Using the formula: size of image = magnification x size of object
Substituting the values, we get:
size of image = 1.5 x 4 cm = 6 cm
Therefore, the nature of the image is virtual, inverted and magnified, and the size of the image is 6 cm.
Calculation of Screen Distance
Using the formula: 1/f = 1/u + 1/v
Where u is the object distance and v is the image distance, and f is the focal length of the mirror.
Substituting the values, we get:
1/-15 = 1/-25 + 1/v
Solving for v, we get:
v = -37.5 cm
Now, using the formula: distance of screen from mirror = v + u
Substituting the values, we get:
distance of screen from mirror = -37.5 cm + (-25 cm) = -62.5 cm
The negative sign indicates that the screen should be placed 62.5 cm behind the mirror.
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