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A car initially at rest, 330m away from stationary observer . It begins to move toward the observer with an acceleration of 1.1 ms-2 , sounding its horn continuously. 20s later the driver stops sounding the horn. The velocity of sound in air is 330. The observer will hear the sound of the horn for a duration of?
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A car initially at rest, 330m away from stationary observer . It begin...
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A car initially at rest, 330m away from stationary observer . It begin...
Given information:
- Distance between the car and the observer (initially) = 330m
- Acceleration of the car = 1.1 m/s^2
- Velocity of sound in air = 330 m/s
- Time period for which the horn was sounded = 20s
Calculating the time taken by the car to reach the observer:
Let's assume the time taken by the car to reach the observer is 't' seconds.
Using the equation of motion:
Distance = Initial velocity * Time + (1/2) * Acceleration * Time^2
We know the initial velocity of the car is 0, so the equation becomes:
Distance = (1/2) * Acceleration * Time^2
Plugging in the values:
330m = (1/2) * 1.1 m/s^2 * t^2
660 = 1.1 * t^2
t^2 = 600
t ≈ 24.49s
Therefore, it takes approximately 24.49 seconds for the car to reach the observer.
Calculating the duration of the sound heard by the observer:
The duration of sound heard by the observer will be the time it takes for the sound waves to travel from the car to the observer.
The total time is divided into two parts:
1. The time when the car is moving towards the observer (t1)
2. The time when the car has stopped moving (t2)
Calculating t1:
t1 is the time from when the car starts moving until it reaches the observer.
t1 = t - 20s (since the horn was sounded for 20s before the driver stopped)
t1 ≈ 24.49s - 20s
t1 ≈ 4.49s
Calculating t2:
t2 is the time it takes for the sound waves to reach the observer after the car has stopped moving.
Distance = Velocity * Time
330m = 330 m/s * t2
t2 = 1s
Therefore, t2 = 1s
Total duration of the sound heard by the observer:
Total duration = t1 + t2
Total duration ≈ 4.49s + 1s
Total duration ≈ 5.49s
Hence, the observer will hear the sound of the horn for a duration of approximately 5.49 seconds.
- Distance between the car and the observer (initially) = 330m
- Acceleration of the car = 1.1 m/s^2
- Velocity of sound in air = 330 m/s
- Time period for which the horn was sounded = 20s
Calculating the time taken by the car to reach the observer:
Let's assume the time taken by the car to reach the observer is 't' seconds.
Using the equation of motion:
Distance = Initial velocity * Time + (1/2) * Acceleration * Time^2
We know the initial velocity of the car is 0, so the equation becomes:
Distance = (1/2) * Acceleration * Time^2
Plugging in the values:
330m = (1/2) * 1.1 m/s^2 * t^2
660 = 1.1 * t^2
t^2 = 600
t ≈ 24.49s
Therefore, it takes approximately 24.49 seconds for the car to reach the observer.
Calculating the duration of the sound heard by the observer:
The duration of sound heard by the observer will be the time it takes for the sound waves to travel from the car to the observer.
The total time is divided into two parts:
1. The time when the car is moving towards the observer (t1)
2. The time when the car has stopped moving (t2)
Calculating t1:
t1 is the time from when the car starts moving until it reaches the observer.
t1 = t - 20s (since the horn was sounded for 20s before the driver stopped)
t1 ≈ 24.49s - 20s
t1 ≈ 4.49s
Calculating t2:
t2 is the time it takes for the sound waves to reach the observer after the car has stopped moving.
Distance = Velocity * Time
330m = 330 m/s * t2
t2 = 1s
Therefore, t2 = 1s
Total duration of the sound heard by the observer:
Total duration = t1 + t2
Total duration ≈ 4.49s + 1s
Total duration ≈ 5.49s
Hence, the observer will hear the sound of the horn for a duration of approximately 5.49 seconds.
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A car initially at rest, 330m away from stationary observer . It begins to move toward the observer with an acceleration of 1.1 ms-2 , sounding its horn continuously. 20s later the driver stops sounding the horn. The velocity of sound in air is 330. The observer will hear the sound of the horn for a duration of?
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A car initially at rest, 330m away from stationary observer . It begins to move toward the observer with an acceleration of 1.1 ms-2 , sounding its horn continuously. 20s later the driver stops sounding the horn. The velocity of sound in air is 330. The observer will hear the sound of the horn for a duration of? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A car initially at rest, 330m away from stationary observer . It begins to move toward the observer with an acceleration of 1.1 ms-2 , sounding its horn continuously. 20s later the driver stops sounding the horn. The velocity of sound in air is 330. The observer will hear the sound of the horn for a duration of? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car initially at rest, 330m away from stationary observer . It begins to move toward the observer with an acceleration of 1.1 ms-2 , sounding its horn continuously. 20s later the driver stops sounding the horn. The velocity of sound in air is 330. The observer will hear the sound of the horn for a duration of?.
A car initially at rest, 330m away from stationary observer . It begins to move toward the observer with an acceleration of 1.1 ms-2 , sounding its horn continuously. 20s later the driver stops sounding the horn. The velocity of sound in air is 330. The observer will hear the sound of the horn for a duration of? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A car initially at rest, 330m away from stationary observer . It begins to move toward the observer with an acceleration of 1.1 ms-2 , sounding its horn continuously. 20s later the driver stops sounding the horn. The velocity of sound in air is 330. The observer will hear the sound of the horn for a duration of? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car initially at rest, 330m away from stationary observer . It begins to move toward the observer with an acceleration of 1.1 ms-2 , sounding its horn continuously. 20s later the driver stops sounding the horn. The velocity of sound in air is 330. The observer will hear the sound of the horn for a duration of?.
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