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In which of the following is there a consistent aecrease in atomic radius as the atomic number increases?
  • a)
    halogens
  • b)
    elements in a period
  • c)
    transition elements
  • d)
    lanthanides
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In which of the following is there a consistent aecrease in atomic rad...
Consistent Decrease in Atomic Radius in Elements in a Period

Explanation:
- Atomic radius is the distance between the nucleus and the outermost electron shell of an atom.
- The atomic radius generally decreases as you move from left to right across a period in the periodic table.
- This is due to the increasing nuclear charge (number of protons) which attracts the electrons closer to the nucleus, making the atomic radius smaller.
- The electrons are in the same energy level or shell, but the effective nuclear charge increases, making the atomic radius smaller.
- The trend is not consistent throughout the periodic table, as there are some exceptions due to electron configurations and shielding effects.

Example:
- In period 3, the atomic radius decreases from sodium to chlorine.
- Sodium has the largest atomic radius in period 3 because it has only three energy levels and one electron in its outermost shell.
- Chlorine, on the other hand, has the smallest atomic radius because it has one more proton than sodium, increasing the effective nuclear charge and pulling the electrons closer to the nucleus.

Conclusion:
- The trend of decreasing atomic radius in elements in a period is due to the increasing nuclear charge and is a fundamental trend in the periodic table.
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Community Answer
In which of the following is there a consistent aecrease in atomic rad...
As the number of electrons in a given shell increase along a period, effective nuclear charge increase.so, atomic size decrease because electrons are held by the atom more strongly.
In halogens, atomic size increase down the group.On the other hand, transition elements and lanthanides do not have consistent decrease.
so, option b is correct.
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Read the passage given below and answer the following questions:Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. However, which mechanism it is based on is related to such factors as the structure of haloalkane, and properties of leaving group, nucleophilic reagent and solvent. Influences of halogen: No matter which mechanism the nucleophilic substitution reaction is based on, the leaving group always leave the central carbon atom with electron pair. This is just the opposite of the situation that nucleophilic reagent attacks the central carbon atom with electron pair. Therefore, the weaker the alkalinity of leaving group is , the more stable the anion formed is and it will be more easier for the leaving group to leave the central carbon atom; that is to say, the reactant is more easier to be substituted. The alkalinity order of halogen ion is I− < Br− < Cl− < F− and the order of their leaving tendency should be I− > Br− > Cl− > F−. Therefore, in four halides with the same alkyl and different halogens, the order of substitution reaction rate is RI > RBr > RCl > RF. In addition, if the leaving group is very easy to leave, many carbocation intermediates are generated in the reaction and the reaction is based on SN1 mechanism. If the leaving group is not easy to leave, the reaction is based on SN2 mechanism. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because polar solvent has a greater stabilizing effect on the transition state than the reactant, thereby reduce activation energy and accelerate the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane in 25° water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. In a word, the level of solvent polarity has influence on both SN1 and SN2 reactions, but with different results. Generally speaking, weak polar solvent is favorable for SN2 reaction, while strong polar solvent is favorable for SN1 reaction, because only under the action of polar solvent can halogenated hydrocarbon dissociate into carbocation and halogen ion and solvents with a strong polarity is favorable for solvation of carbocation, increasing its stability. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example, ethanol containing water).Q. SN1 reaction will be fastest in which of the following solvents?

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In which of the following is there a consistent aecrease in atomic radius as the atomic number increases?a)halogensb)elements in a periodc)transition elementsd)lanthanidesCorrect answer is option 'B'. Can you explain this answer?
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