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Molecules of benzoic acid dimerize in benzene. W gm of the acid dissolved in 30 gm benzene shows a depression in freezing point equal to 2 Kelvin if the percentage of association of acid to form dimer in solution is 80 then w value is given that f equals to 5 Kelvin kg per mole and molar mass of benzoic acid 122 gram per mole?
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Molecules of benzoic acid dimerize in benzene. W gm of the acid dissol...
2(C6H5COOH ) C6H6/30g( C6H5COOH)2 ∆fT=i×Kf×m 2= 0.6 × 5 × W×1000/122 × 30 ( i = 1 - 0.8 + 0.4 = 0.6 ) W= 2.44 = 2.4 g
Community Answer
Molecules of benzoic acid dimerize in benzene. W gm of the acid dissol...
Understanding the Problem
To find the mass of benzoic acid (w) that dimerizes in benzene, we need to utilize the freezing point depression formula and the provided data.
Given Data
- Depression in freezing point (ΔTf) = 2 K
- Freezing point depression constant (f) = 5 K kg/mol
- Molar mass of benzoic acid = 122 g/mol
- Mass of benzene = 30 g
- Percentage of association (dimerization) = 80%
Calculating the Moles of Solvent
- Moles of benzene = Mass (g) / Molar mass (g/mol)
- Molar mass of benzene = 78 g/mol
- Moles of benzene = 30 g / 78 g/mol ≈ 0.3857 mol
Using Freezing Point Depression Formula
- ΔTf = i * f * m
- Where i = van 't Hoff factor and m = molality
Since 80% of benzoic acid dimerizes, the effective i = 1.2 (1 for monomers + 0.2 for undimerized).
Calculating Molality
- Rearranging gives us: m = ΔTf / (i * f)
- m = 2 K / (1.2 * 5 K kg/mol) = 0.3333 mol/kg
Finding the Moles of Benzoic Acid
- Molality (m) = moles of solute / kg of solvent
- 0.3333 mol/kg = moles of benzoic acid / 0.03 kg
- Moles of benzoic acid = 0.3333 mol/kg * 0.03 kg = 0.01 mol
Calculating Mass of Benzoic Acid (w)
- w = moles * molar mass
- w = 0.01 mol * 122 g/mol = 1.22 g
Final Result
- Therefore, the mass of benzoic acid (w) is approximately 1.22 g.
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Molecules of benzoic acid dimerize in benzene. W gm of the acid dissolved in 30 gm benzene shows a depression in freezing point equal to 2 Kelvin if the percentage of association of acid to form dimer in solution is 80 then w value is given that f equals to 5 Kelvin kg per mole and molar mass of benzoic acid 122 gram per mole?
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Molecules of benzoic acid dimerize in benzene. W gm of the acid dissolved in 30 gm benzene shows a depression in freezing point equal to 2 Kelvin if the percentage of association of acid to form dimer in solution is 80 then w value is given that f equals to 5 Kelvin kg per mole and molar mass of benzoic acid 122 gram per mole? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Molecules of benzoic acid dimerize in benzene. W gm of the acid dissolved in 30 gm benzene shows a depression in freezing point equal to 2 Kelvin if the percentage of association of acid to form dimer in solution is 80 then w value is given that f equals to 5 Kelvin kg per mole and molar mass of benzoic acid 122 gram per mole? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Molecules of benzoic acid dimerize in benzene. W gm of the acid dissolved in 30 gm benzene shows a depression in freezing point equal to 2 Kelvin if the percentage of association of acid to form dimer in solution is 80 then w value is given that f equals to 5 Kelvin kg per mole and molar mass of benzoic acid 122 gram per mole?.
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