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If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?
- a)3.12 x 1013
- b)3.13 x 1013
- c)3.1 x 1013
- d)3.2 x 1013
Correct answer is option 'A'. Can you explain this answer?
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To determine the number of fissions per second required to produce a power of 1 kW, we need to consider the energy released per fission and the definition of power.
1. Energy released per fission:
Given that 200 MeV of energy is released in the fission of a single nucleus of 92 U235, we need to convert this energy to joules (J) for further calculations.
1 MeV = 1.6 x 10^-13 J
So, 200 MeV = 200 x 1.6 x 10^-13 J = 3.2 x 10^-11 J
2. Power:
Power is defined as the rate at which energy is transferred or work is done. It is measured in watts (W), where 1 W = 1 J/s.
To find the number of fissions per second, we can use the following formula:
Power = Number of fissions per second x Energy released per fission
Since power is given as 1 kW (1 kW = 1000 W) and the energy released per fission is 3.2 x 10^-11 J, we can rearrange the formula to solve for the number of fissions per second:
Number of fissions per second = Power / Energy released per fission
Number of fissions per second = (1 kW) / (3.2 x 10^-11 J)
Number of fissions per second = (1000 W) / (3.2 x 10^-11 J)
Number of fissions per second = 3.125 x 10^13 fissions/s
Therefore, the correct answer is option A: 3.12 x 10^13 fissions/s.
1. Energy released per fission:
Given that 200 MeV of energy is released in the fission of a single nucleus of 92 U235, we need to convert this energy to joules (J) for further calculations.
1 MeV = 1.6 x 10^-13 J
So, 200 MeV = 200 x 1.6 x 10^-13 J = 3.2 x 10^-11 J
2. Power:
Power is defined as the rate at which energy is transferred or work is done. It is measured in watts (W), where 1 W = 1 J/s.
To find the number of fissions per second, we can use the following formula:
Power = Number of fissions per second x Energy released per fission
Since power is given as 1 kW (1 kW = 1000 W) and the energy released per fission is 3.2 x 10^-11 J, we can rearrange the formula to solve for the number of fissions per second:
Number of fissions per second = Power / Energy released per fission
Number of fissions per second = (1 kW) / (3.2 x 10^-11 J)
Number of fissions per second = (1000 W) / (3.2 x 10^-11 J)
Number of fissions per second = 3.125 x 10^13 fissions/s
Therefore, the correct answer is option A: 3.12 x 10^13 fissions/s.
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If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer?
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