NEET Exam > NEET Questions > If 200 Mev energy is released in the fission ...
Start Learning for Free
If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?
- a)3.12 x 1013
- b)3.13 x 1013
- c)3.1 x 1013
- d)3.2 x 1013
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
If 200 Mev energy is released in the fission of a single nucleus of 92...
Free Test
FREE
| Start Free Test |
Community Answer
If 200 Mev energy is released in the fission of a single nucleus of 92...
To determine the number of fissions per second required to produce a power of 1 kW, we need to consider the energy released per fission and the definition of power.
1. Energy released per fission:
Given that 200 MeV of energy is released in the fission of a single nucleus of 92 U235, we need to convert this energy to joules (J) for further calculations.
1 MeV = 1.6 x 10^-13 J
So, 200 MeV = 200 x 1.6 x 10^-13 J = 3.2 x 10^-11 J
2. Power:
Power is defined as the rate at which energy is transferred or work is done. It is measured in watts (W), where 1 W = 1 J/s.
To find the number of fissions per second, we can use the following formula:
Power = Number of fissions per second x Energy released per fission
Since power is given as 1 kW (1 kW = 1000 W) and the energy released per fission is 3.2 x 10^-11 J, we can rearrange the formula to solve for the number of fissions per second:
Number of fissions per second = Power / Energy released per fission
Number of fissions per second = (1 kW) / (3.2 x 10^-11 J)
Number of fissions per second = (1000 W) / (3.2 x 10^-11 J)
Number of fissions per second = 3.125 x 10^13 fissions/s
Therefore, the correct answer is option A: 3.12 x 10^13 fissions/s.
1. Energy released per fission:
Given that 200 MeV of energy is released in the fission of a single nucleus of 92 U235, we need to convert this energy to joules (J) for further calculations.
1 MeV = 1.6 x 10^-13 J
So, 200 MeV = 200 x 1.6 x 10^-13 J = 3.2 x 10^-11 J
2. Power:
Power is defined as the rate at which energy is transferred or work is done. It is measured in watts (W), where 1 W = 1 J/s.
To find the number of fissions per second, we can use the following formula:
Power = Number of fissions per second x Energy released per fission
Since power is given as 1 kW (1 kW = 1000 W) and the energy released per fission is 3.2 x 10^-11 J, we can rearrange the formula to solve for the number of fissions per second:
Number of fissions per second = Power / Energy released per fission
Number of fissions per second = (1 kW) / (3.2 x 10^-11 J)
Number of fissions per second = (1000 W) / (3.2 x 10^-11 J)
Number of fissions per second = 3.125 x 10^13 fissions/s
Therefore, the correct answer is option A: 3.12 x 10^13 fissions/s.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer?
Question Description
If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer?.
If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer?.
Solutions for If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer?, a detailed solution for If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice If 200 Mev energy is released in the fission of a single nucleus of 92 U 235 , how many fissions must occur per second to produce a power of 1 kW?a)3.12 x 1013b)3.13x 1013c)3.1 x 1013d)3.2 x 1013Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup