NEET Exam > NEET Questions > For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E&...
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For the cell
Zn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,
E°Cu2+/Cu = 0.34 V
and for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,
E°cell - 0.46V hence, E°cell of th ecell
Zn | Zn2+(1M) || Ag+ (1M) | Ag is
Zn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,
E°Cu2+/Cu = 0.34 V
and for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,
E°cell - 0.46V hence, E°cell of th ecell
Zn | Zn2+(1M) || Ag+ (1M) | Ag is
- a)-0.04 V
- b)+ 0.04 V
- c)+0.30 V
- d)+ 1.56 V
Correct answer is option 'D'. Can you explain this answer?
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For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°...
During transcription the nucleotides present on templete stand get transcribedand the resulted seqence are complementary to the templete stand but with uracil in place of thymine.hence B
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For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°...
Given Data:
E°cell Zn | Zn2+(1M) || Cu2+(1M) | Cu = 1.10 V
E°cell Cu2+/Cu = 0.34 V
E°cell Cu | Cu2+(1M) || Ag+(1M) | Ag = 0.46 V
Calculating E°cell for Zn | Zn2+(1M) || Ag+ (1M) | Ag:
1. Calculate E°cell for the overall reaction:
Zn(s) + Cu2+(aq) → Cu(s) + Zn2+(aq)
E°cell = E°cell Zn | Zn2+ - E°cell Cu2+/Cu
E°cell = 1.10 V - 0.34 V
E°cell = 0.76 V
2. Calculate E°cell for the 2nd half-reaction:
Cu(s) + 2Ag+(aq) → 2Ag(s) + Cu2+(aq)
E°cell = -E°cell Cu | Cu2+ - E°cell Ag+ | Ag
E°cell = -0.46 V
E°cell = -0.46 V
3. Add the E°cell values for both half-reactions to get the E°cell for Zn | Zn2+(1M) || Ag+ (1M) | Ag:
E°cell = 0.76 V - 0.46 V
E°cell = 1.56 V
Therefore, the E°cell for the cell Zn | Zn2+(1M) || Ag+ (1M) | Ag is 1.56 V, which corresponds to option 'D'.
E°cell Zn | Zn2+(1M) || Cu2+(1M) | Cu = 1.10 V
E°cell Cu2+/Cu = 0.34 V
E°cell Cu | Cu2+(1M) || Ag+(1M) | Ag = 0.46 V
Calculating E°cell for Zn | Zn2+(1M) || Ag+ (1M) | Ag:
1. Calculate E°cell for the overall reaction:
Zn(s) + Cu2+(aq) → Cu(s) + Zn2+(aq)
E°cell = E°cell Zn | Zn2+ - E°cell Cu2+/Cu
E°cell = 1.10 V - 0.34 V
E°cell = 0.76 V
2. Calculate E°cell for the 2nd half-reaction:
Cu(s) + 2Ag+(aq) → 2Ag(s) + Cu2+(aq)
E°cell = -E°cell Cu | Cu2+ - E°cell Ag+ | Ag
E°cell = -0.46 V
E°cell = -0.46 V
3. Add the E°cell values for both half-reactions to get the E°cell for Zn | Zn2+(1M) || Ag+ (1M) | Ag:
E°cell = 0.76 V - 0.46 V
E°cell = 1.56 V
Therefore, the E°cell for the cell Zn | Zn2+(1M) || Ag+ (1M) | Ag is 1.56 V, which corresponds to option 'D'.
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For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer?
Question Description
For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer?.
For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer?.
Solutions for For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice For the cellZn | Zn2+(1M) || Cu2+(1M) |Cu, E° ceIl is 1.10V,E°Cu2+/Cu= 0.34 Vand for the cell Cu | Cu2+(1M) || Ag+(1M) | Ag,E°cell- 0.46V hence, E°cellof th ecellZn | Zn2+(1M) || Ag+ (1M) | Ag isa)-0.04 Vb)+ 0.04 Vc)+0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice NEET tests.
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