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In a single slit diffraction with wave length 500nm and lens of diameter 0.1mm then width of central maxima obtain on screen at a distance of 1m will be?
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Single Slit Diffraction Overview
Single slit diffraction occurs when light passes through a narrow slit, creating a pattern of light and dark bands on a screen. The width of the central maximum can be calculated using the formula:
Width of central maximum = 2 * (Distance to screen) * (Wavelength / Slit width).
Given Parameters
- Wavelength (λ): 500 nm (or 500 x 10^-9 m)
- Diameter of the slit: 0.1 mm (or 0.1 x 10^-3 m)
- Distance to the screen (L): 1 m
Calculating the Slit Width
- The slit width (a) is equal to the diameter in this case. Thus, a = 0.1 mm = 0.1 x 10^-3 m.
Applying the Formula
- Now, plug the values into the formula:
Width of central maximum = 2 * L * (λ / a)
Width of central maximum = 2 * 1 * (500 x 10^-9 / 0.1 x 10^-3)
Calculating the Result
- First, calculate λ / a:
λ / a = (500 x 10^-9) / (0.1 x 10^-3) = 5 x 10^-3
- Now, substituting back:
Width of central maximum = 2 * 1 * 5 x 10^-3 = 0.01 m or 10 mm.
Conclusion
The width of the central maximum on the screen at a distance of 1 m is 10 mm. This indicates that the central bright fringe is relatively broad, showcasing the wave nature of light as it diffracts through the slit.
Single slit diffraction occurs when light passes through a narrow slit, creating a pattern of light and dark bands on a screen. The width of the central maximum can be calculated using the formula:
Width of central maximum = 2 * (Distance to screen) * (Wavelength / Slit width).
Given Parameters
- Wavelength (λ): 500 nm (or 500 x 10^-9 m)
- Diameter of the slit: 0.1 mm (or 0.1 x 10^-3 m)
- Distance to the screen (L): 1 m
Calculating the Slit Width
- The slit width (a) is equal to the diameter in this case. Thus, a = 0.1 mm = 0.1 x 10^-3 m.
Applying the Formula
- Now, plug the values into the formula:
Width of central maximum = 2 * L * (λ / a)
Width of central maximum = 2 * 1 * (500 x 10^-9 / 0.1 x 10^-3)
Calculating the Result
- First, calculate λ / a:
λ / a = (500 x 10^-9) / (0.1 x 10^-3) = 5 x 10^-3
- Now, substituting back:
Width of central maximum = 2 * 1 * 5 x 10^-3 = 0.01 m or 10 mm.
Conclusion
The width of the central maximum on the screen at a distance of 1 m is 10 mm. This indicates that the central bright fringe is relatively broad, showcasing the wave nature of light as it diffracts through the slit.
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In a single slit diffraction with wave length 500nm and lens of diameter 0.1mm then width of central maxima obtain on screen at a distance of 1m will be?
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In a single slit diffraction with wave length 500nm and lens of diameter 0.1mm then width of central maxima obtain on screen at a distance of 1m will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a single slit diffraction with wave length 500nm and lens of diameter 0.1mm then width of central maxima obtain on screen at a distance of 1m will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a single slit diffraction with wave length 500nm and lens of diameter 0.1mm then width of central maxima obtain on screen at a distance of 1m will be?.
In a single slit diffraction with wave length 500nm and lens of diameter 0.1mm then width of central maxima obtain on screen at a distance of 1m will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a single slit diffraction with wave length 500nm and lens of diameter 0.1mm then width of central maxima obtain on screen at a distance of 1m will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a single slit diffraction with wave length 500nm and lens of diameter 0.1mm then width of central maxima obtain on screen at a distance of 1m will be?.
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